HDOJ 題目5097 Page Rank(矩陣運算,模擬)
Page Rank
Time Limit: 3000/1500 MS (Java/Others) Memory Limit: 100000/100000 K (Java/Others)Total Submission(s): 280 Accepted Submission(s): 75
Problem Description Evaluation and rank of web pages is a hot topic for many internet companies and researchers. PageRank is a link analysis tool and it assigns a numerical weighting to each element of a hyperlinked set of documents, such as the World Wide Web, with the purpose of "measuring" its relative importance within the set. The algorithm may be applied to any collection of entities with reciprocal quotations and references. The numerical weight that it assigns to any given element E is referred to as the PageRank of E and denoted by . Other factors like Author Rank can contribute to the importance of an entity.
For simplicity, in this problem PageRank vector q is defined as q = Gq, Where
For the example on the right, we have:
Denote the current PageRank vector and the next PageRank vector by qcur and qnext respectively. The process is to compute the iterative powering for finding the first eigenvector.
The computation ends until for some small ε(10-10).
Input The input contains many test cases.
For each case, there are multiple lines. The first line contains an integer N(N<=3000), which represents the number of pages. Then a N*N zero-one matrix follows. The element Eij (0 <= i, j < N) on the matrix represents whether the i-th page has a hyper link to the j-th page.
Output Output one line with the eigenvector. The numbers should be separated by a space and be correctly rounded to two decimal places.
Sample Input
4 0111 0011 0001 0100
Sample Output
0.15 1.49 0.83 1.53
Source
field=problem&key=2014%C9%CF%BA%A3%C8%AB%B9%FA%D1%FB%C7%EB%C8%FC%A1%AA%A1%AA%CC%E2%C4%BF%D6%D8%CF%D6%A3%A8%B8%D0%D0%BB%C9%CF%BA%A3%B4%F3%D1%A7%CC%E1%B9%A9%CC%E2%C4%BF%A3%A9&source=1&searchmode=source" style="color:rgb(26,92,200); text-decoration:none">2014上海全國邀請賽——題目重現(感謝上海大學提供題目)
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Problem : 5097 ( Page Rank ) Judge Status : Accepted RunId : 14492913 Language : C++ Author : lwj1994 Code Render Status : Rendered By HDOJ C++ Code Render Version 0.01 Beta #include<stdio.h> #include<string.h> #include<math.h> #define eps 1e-10 char map[3030]; double ans[3030][3030]; double q[2][3030]; int n; void muti(double a[][3030],double num) { int i,j; for(i=0;i<n;i++) { for(j=0;j<n;j++) a[i][j]*=num; } } void add(double a[][3030],double b[][3030]) { int i,j; for(i=0;i<n;i++) { for(j=0;j<n;j++) a[i][j]+=b[i][j]; } } int jud() { double ans=0; int i; for(i=0;i<n;i++) { ans+=(q[0][i]-q[1][i])*(q[0][i]-q[1][i]); } //ans=sqrt(ans); if(fabs(ans)<eps) return 1; return 0; } int main() { //int n; while(scanf("%d",&n)!=EOF) { int i,j; double a=0.85; memset(ans,0,sizeof(ans)); for(i=0;i<n;i++) { int sum=0; scanf("%s",&map); for(j=0;j<n;j++) { if(map[j]=='1') sum++; //U[i][j]=1; } for(j=0;j<n;j++) { if(map[j]=='1') ans[j][i]=1.0/sum; } } muti(ans,a); // muti(U,1.0/n*(0.15)); // printf("\n"); // add(ans,U); for(i=0;i<n;i++) for(j=0;j<n;j++) ans[i][j]+=(0.15/n); int p=0; for(i=0;i<n;i++) { q[p][i]=1; q[p^1][i]=0; } //mmuti(q[p],ans,q[p^1]); //p^=1; while(!jud()) { //q[p^1]=mmuti(q[p],ans); for(i=0;i<n;i++) { q[p^1][i]=0; for(j=0;j<n;j++) q[p^1][i]+=q[p][j]*ans[i][j]; } p^=1; } printf("%.2lf",q[p][0]); for(i=1;i<n;i++) { printf(" %.2lf",q[p][i]); } printf("\n"); } }
HDOJ 題目5097 Page Rank(矩陣運算,模擬)