1 /*
 2 struct ListNode {
 3     int val;
 4     struct ListNode *next;
 5     ListNode(int x) :
 6         val(x), next(NULL) {
 7     }
 8 };
 9 */
10 class Solution {
11 public:
12     //通過快慢指針找到在環中的相遇點
 

13     ListNode* MeetingNode(ListNode *pHead)
14     {
15         //找到在環中的結點--快慢指針
16         if(pHead == NULL)
17             return NULL;
18         ListNode *slow = pHead;
19         ListNode *fast = pHead;
20         while(fast != NULL && fast->next != NULL)
21         {
22             slow = slow->next;
 
23             fast = fast->next->next;
24             if(fast == slow)//註意此處先移動，再判斷
25                 return fast;
26         }
27         return NULL;
28     }
29     ListNode* EntryNodeOfLoop(ListNode* pHead)
30     {
31         ListNode *meetNode = MeetingNode(pHead);
32         if(meetNode == NULL)
 
33             return NULL;
34         int nodesInLoop = 1;
35         ListNode *pNode1 = meetNode;
36         while(pNode1->next != meetNode)
37         {
38             pNode1 = pNode1->next;
39             nodesInLoop++;
40         }
41         pNode1 = pHead;
42         for(int i=0;i<nodesInLoop;i++)
43         {
44             pNode1 = pNode1->next;    
45         }
46         ListNode *pNode2 = pHead;
47         while(pNode1 != pNode2)
48         {
49             pNode1 = pNode1->next;
50             pNode2 = pNode2->next;    
51         }
52         return pNode1;
53     }
54 };

55、劍指offer--鏈表中環的入口結點