Your friend is typing his name into a keyboard. Sometimes, when typing a character c, the key might get long pressed, and the character will be typed 1 or more times.

You examine the typed characters of the keyboard. Return True if it is possible that it was your friends name, with some characters (possibly none) being long pressed.

Example 1:

Input: name = "alex", typed = "aaleex"
Output: true
Explanation: ‘a‘ and ‘e‘ in ‘alex‘ were long pressed.

Example 2:

Input: name = "saeed", typed = "ssaaedd"
Output: false
Explanation: ‘e‘ must have been pressed twice, but it wasn‘t in the typed output.

Example 3:

Input: name = "leelee", typed = "lleeelee"
Output: true
 

Example 4:

Input: name = "laiden", typed = "laiden"
Output: true
Explanation: It‘s not necessary to long press any character.

Note:

1. name.length <= 1000
2. typed.length <= 1000
3. The characters of name and typed are lowercase letters.

你的朋友正在使用鍵盤輸入他的名字 name。偶爾，在鍵入字符 c 時，按鍵可能會被長按，而字符可能被輸入 1 次或多次。

你將會檢查鍵盤輸入的字符 typed。如果它對應的可能是你的朋友的名字（其中一些字符可能被長按），那麽就返回 True。

示例 1：

輸入：name = "alex", typed = "aaleex"
輸出：true
解釋：‘alex‘ 中的 ‘a‘ 和 ‘e‘ 被長按。

示例 2：

輸入：name = "saeed", typed = "ssaaedd"
輸出：false
解釋：‘e‘ 一定需要被鍵入兩次，但在 typed 的輸出中不是這樣。

示例 3：

輸入：name = "leelee", typed = "lleeelee"
輸出：true

示例 4：

輸入：name = "laiden", typed = "laiden"
輸出：true
解釋：長按名字中的字符並不是必要的。

提示：

1. name.length <= 1000
2. typed.length <= 1000
3. name 和 typed 的字符都是小寫字母。

36ms

 1 class Solution {
 2     func isLongPressedName(_ name: String, _ typed: String) -> Bool {
 3         var p:Int = 0
 4         for num in 0..<typed.count
 5         {
 6             var typeIndex = typed.index(typed.startIndex,offsetBy: num)
 7             var nameIndex = name.index(name.startIndex,offsetBy: p)
 8             if p < name.count && typed[typeIndex] == name[nameIndex]
 9             {
10                 p += 1
11             }
12             else
13             {
14                 if num > 0 && typed[typeIndex] == typed[typed.index(typed.startIndex,offsetBy: num - 1)]
15                 {
16                     continue
17                 }
18                 else
19                 {
20                     return false
21                 }
22             }
23         }
24         return p == name.count
25     }
26 }

[Swift]LeetCode925. 長按鍵入 | Long Pressed Name