NUMPY數組及處理:效率對
阿新 • • 發佈:2018-10-22
now() mage sta sat list str cal start arange
import time print (time.strftime("%Y-%m-%d %H:%M:%S", time.localtime())) print (time.strftime("%a %b %d %H:%M:%S %Y", time.localtime())) a = "Sat Mar 28 22:24:24 2016" print (time.mktime(time.strptime(a ,"%a %b %d %H:%M:%S %Y")))
stat = "{0:%Y}年{0:%m}月{0:%d}日星期{0:%w} {0:%H}時{0:%M}分{0:%S}秒".format(datetime.now()) end = datetime.strptime(‘2018-10-25 22:00‘,"%Y-%m-%d %H:%M") print(datetime.now()-end)
#用列表+循環實現,並包裝成函數 def Godo(n): a = list(range(10)) b = list(range(0,n*5,5)) c = [] for i in range(len(a)): c.append(a[i]**2+b[i]**3) return (c) print(Godo(10)) #用numpy實現,並包裝成函數 import numpy def Godo(n): a = numpy.arange(10) b = numpy.arange(0,50, 5) c = a + breturn(c) print(Godo(10)) from datetime import datetime start = datetime.now() Godo(100000) delta = datetime.now()-start print(delta) start = datetime.now() Godo(100000) delta = datetime.now()-start print(delta)
NUMPY數組及處理:效率對