計算兩個時間的差
阿新 • • 發佈:2019-02-09
//獲取公曆年的天數
int year_alldays(int year)
{
if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0) return 366; else return 365;
}
//獲取公曆年初至某整月的天數
int year_sumday(int year, int month)
{
int sum = 0;
int rui[12] = { 31,29,31,30,31,30,31,31,30,31,30,31 };
int ping[12] = { 31,28,31,30,31,30,31,31 ,30,31,30,31 };
int ruiflag = 0;
if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0) ruiflag = 1;
for (int index = 0; index < month - 1; index++)
{
if (ruiflag == 1) sum += rui[index]; else sum += ping[index];
}
return sum;
}
//獲取從公曆1800年1月25日至當前日期的總天數
int get_g_alldays(int year, int month, int day)
{
int i = 1800, days = -24;
while (i < year)
{
days += year_alldays(i);
i++;
}
int days2 = year_sumday(year, month);
return days + days2 + day;
}
int main()
{
int year1, year2, month1, month2, day1, day2;
char buf[30 ] ="", buf1[30]="", buf2[30]="";
sscanf(temp, "%[^-]-%[^-]-%[^-]", buf, buf1, buf2);
//printf("%s %s %s\n", buf, buf1, buf2);
year1 = atoi(buf);
month1 = atoi(buf1);
day1 = atoi(buf2);
sscanf(EndTime, "%[^-]-%[^-]-%[^-]", buf, buf1, buf2);
year2 = atoi(buf);
month2 = atoi(buf1);
day2 = atoi(buf2);
int days1 = get_g_alldays(year1, month1, day1);
int days2 = get_g_alldays(year2, month2, day2);
int days = 0;
if (days1 >= days2)
days = days1 - days2;
else
days = days2 - days1;
}