【LeetCode】371. Sum of Two Integers
Problem:Calculate the sum of two integers a and b, but you are not allowed to use the operator +
and -
.
Example:
Given a = 1 and b = 2, return 3.
題目:計算a和b的和,不使用加減運算子。
思路:使用異或,與等邏輯運算。(參考計算機組成原理中補碼加減法等)
使用異或保留二進位制中的不同位,與運算保留相同位,左移則實現進位操作,再用異或運算實現相加,同時與運算左移實現進位,直至與運算後為0停止。
程式碼:
class Solution {
public int getSum(int a, int b) {
return (b==0)?a:getSum(a^b,(a&b)<<1);
//return ((a&b)<<1)|(a^b);
}
}
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#leetcode#Sum of Two Integers
Calculate the sum of two integers a and b, but you are not allowed to use the operator + and -. Example: