LeetCode Unique Binary Search Trees
對於選取的點,它的返回值應該是它的不同左子樹的個數*他的不同右子樹的個數。
邊界調節,當n=0時,返回1,只返回一個空樹,當n=1時,返回1,只有一個節點的樹。
AC Java:
public class Solution { public int numTrees(int n) { int[] arr = new int[n+1]; arr[0] = 1; arr[1] = 1; for(int i = 2; i<=n; i++){ for(int j = 0; j < i; j++){ arr[i]+=arr[j]*arr[i-1-j]; } } return arr[n]; } }
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