python批量處理檔案或資料夾
阿新 • • 發佈:2020-01-09
本文例項為大家分享了python批量處理檔案或資料夾的具體程式碼,供大家參考,具體內容如下
# -*- coding: utf-8 -*- import os,shutil import sys import numpy as np ##########批量刪除不同資料夾下的同名資料夾############# def arrange_file(dir_path0): for dirpath,dirnames,filenames in os.walk(dir_path0): if 'my_result' in dirpath: # print(dirpath) shutil.rmtree(dirpath) ##########批量在不同資料夾下新建同名子資料夾並把檔案搬移到子資料夾############# def arrange_file(dir_path0): for dirpath,filenames in os.walk(dir_path0): for files in filenames: total_path = os.path.join(dirpath,files) root_path,file_path = total_path.split(dir_path,1) if 'png' in file_path: new_file_path = '.' + file_path[:-9] + 'new_file_name/' # print(file_path) # print(new_file_path) # print(new_file_path + file_path[-9:]) # if not os.path.exists(new_file_path): # os.makedirs(new_file_path) # shutil.move('.' + file_path,new_file_path + file_path[-9:]) ##########批量刪除不同資料夾下符合條件的檔案################## def arrange_file(dir_path0): for dirpath,files) # print(total_path) if 'jpg' in total_path and 'labels' in total_path: img = cv2.imread(total_path) if np.sum(img) == 0: print(total_path) os.remove(total_path) ###########批量把檔案搬移到上一層資料夾並刪除當前資料夾######## def arrange_file(dir_path0): for dirpath,file_path = total_path.split(dir_path0,1) # print(file_path[:-48]) # return 0 if 'jpg' in file_path: new_file_path = dir_path0 + file_path[:-48] shutil.move(dir_path0 + file_path,new_file_path + file_path[-9:]) for dirpath,filenames in os.walk(dir_path0): file_path = dirpath.split('./your_total_path')[1] if 'keywords' in file_path: # print(dirpath) shutil.rmtree(dirpath) if __name__=='__main__': dir_path0 = './your_total_path' arrange_file(dir_path0)
以上就是本文的全部內容,希望對大家的學習有所幫助,也希望大家多多支援我們。