js實現適配移動端的拖動效果
阿新 • • 發佈:2020-01-15
本文例項為大家分享了js實現適配移動端的拖動效果,供大家參考,具體內容如下
1.html
<div id="div1"> <div id="div2"></div> </div>
2.js
var flag = false; var cur = { x: 0,y: 0 } var nx,ny,dx,dy,x,y; function down() { flag = true; var touch; if(event.touches) { touch = event.touches[0]; } else { touch = event; } cur.x = touch.clientX; cur.y = touch.clientY; dx = div2.offsetLeft; dy = div2.offsetTop; } function move() { if(flag) { var touch; if(event.touches) { touch = event.touches[0]; } else { touch = event; } nx = touch.clientX - cur.x; ny = touch.clientY - cur.y; x = dx + nx; y = dy + ny; div2.style.left = x + "px"; div2.style.top = y + "px"; //阻止頁面的滑動預設事件 document.addEventListener("touchmove",function() { event.preventDefault(); },false); } } //滑鼠釋放時候的函式 function end() { flag = false; } var div2 = document.getElementById("div2"); div2.addEventListener("mousedown",function() { down(); },false); div2.addEventListener("touchstart",false) div2.addEventListener("mousemove",function() { move(); },false); div2.addEventListener("touchmove",false) document.body.addEventListener("mouseup",function() { end(); },false); div2.addEventListener("touchend",function() { end(); },false);
效果:
以上就是本文的全部內容,希望對大家的學習有所幫助,也希望大家多多支援我們。