257. Binary Tree Paths
阿新 • • 發佈:2020-10-21
package LeetCode_257 /** * 257. Binary Tree Paths * https://leetcode.com/problems/binary-tree-paths/ * Given a binary tree, return all root-to-leaf paths. Note: A leaf is a node with no children. Example: Input: 1 / \ 2 3 \ 5 Output: ["1->2->5", "1->3"] Explanation: All root-to-leaf paths are: 1->2->5, 1->3 **/ class TreeNode(var `val`:Int){ var left:TreeNode?=null var right:TreeNode?=null } class Solution { /* * solution: recursion, Time complexity:O(n), Space complexity:O(n) * */ private val list = ArrayList<String>() fun binaryTreePaths(root: TreeNode?): List<String> { val path= "" return list } private fun help(root: TreeNode?, list:ArrayList<String>, path_: String){ if (root==null){ return } val path = "$path_->${root.`val`}" if (root.left == null && root.right == null){ //is leaf,add path without "->" in head of path//for example: path:->1->2->5, just insert 1->2->5 into list list.add(path.substring(2)) return } if (root.left!=null){ help(root.left, list, path) } if (root.right!=null){ help(root.right, list, path) } } }