leetcode707 - Design Linked List - medium
阿新 • • 發佈:2020-10-25
Design yourimplementation of the linked list. You can choose to use a singly or doubly linked list.
A node in a singlylinked list should have two attributes:val
andnext
.val
is the value of the current node, andnext
isapointer/reference to the next node.
If you want to use the doubly linked list,you will needone more attributeprev
Implement theMyLinkedList
class:
MyLinkedList()
InitializestheMyLinkedList
object.int get(int index)
Get the value oftheindexth
node in the linked list. If the index is invalid, return-1
.void addAtHead(int val)
val
before the first element of the linked list. After the insertion, the new node will be the first node of the linked list.void addAtTail(int val)
Append a node of valueval
as the last element of the linked list.void addAtIndex(int index, int val)
Add a node of valueval
before theindexth
index
equals the length of the linked list, the node will be appended to the end of the linked list. Ifindex
is greater than the length, the nodewill not be inserted.void deleteAtIndex(int index)
Deletetheindexth
node in the linked list, if the index is valid.
Example 1:
Input ["MyLinkedList", "addAtHead", "addAtTail", "addAtIndex", "get", "deleteAtIndex", "get"] [[], [1], [3], [1, 2], [1], [1], [1]] Output [null, null, null, null, 2, null, 3] Explanation MyLinkedList myLinkedList = new MyLinkedList(); myLinkedList.addAtHead(1); myLinkedList.addAtTail(3); myLinkedList.addAtIndex(1, 2); // linked list becomes 1->2->3 myLinkedList.get(1); // return 2 myLinkedList.deleteAtIndex(1); // now the linked list is 1->3 myLinkedList.get(1); // return 3
Constraints:
0 <= index, val <= 1000
- Please do not use the built-in LinkedList library.
- At most
2000
calls will be made toget
,addAtHead
,addAtTail
,addAtIndex
anddeleteAtIndex
.
class MyLinkedList { public: struct ListNode{ ListNode* next; int val; ListNode(int x) : val(x), next(nullptr) {} }; ListNode* head; /** Initialize your data structure here. */ MyLinkedList() { head = nullptr; } /** Get the value of the index-th node in the linked list. If the index is invalid, return -1. */ int get(int index) { if (index < 0) return -1; if (!head) return -1; ListNode* p = head; for (int i=0; i<index; i++){ if (p->next) p = p->next; else return -1; } return p->val; } /** Add a node of value val before the first element of the linked list. After the insertion, the new node will be the first node of the linked list. */ void addAtHead(int val) { ListNode* newNode = new ListNode(val); newNode->next = head; head = newNode; } /** Append a node of value val to the last element of the linked list. */ void addAtTail(int val) { if (!head){ addAtHead(val); return; } ListNode* newNode = new ListNode(val); ListNode* p = head; while (p && p->next){ p = p->next; } p->next = newNode; } /** Add a node of value val before the index-th node in the linked list. If index equals to the length of linked list, the node will be appended to the end of linked list. If index is greater than the length, the node will not be inserted. */ void addAtIndex(int index, int val) { if (index < 0) return; if (index == 0){ addAtHead(val); return; } ListNode* newNode = new ListNode(val); ListNode* p = head; for (int i=0; i<index-1; i++){ if (p->next) p = p->next; else return; } ListNode* next = p->next; p->next = newNode; newNode->next = next; } /** Delete the index-th node in the linked list, if the index is valid. */ void deleteAtIndex(int index) { if (index < 0) return; if (index == 0){ head = head->next; return; } ListNode* p = head; for (int i=0; i<index-1; i++){ if (p->next) p = p->next; else return; } if (p->next){ ListNode* next = p->next->next; p->next = next; } else p->next = nullptr; } };