比較APP版本號大小
阿新 • • 發佈:2020-11-05
public static void main(String[] args) { String[] versions = { "1.9", "1.10", "1.0" }; for (int i = versions.length - 1; i > 0; i--) { for (int j = 0; j < i; j++) { if (compareAppVersion(versions[i], versions[j]) > 0) { String temp = versions[j]; versions[j] = versions[j + 1]; versions[j + 1] = temp; } } } System.out.println(JSON.toJSONString(versions)); } /** * 比較APP版本號的大小 * 1、前者大則返回一個正數 * 2、後者大返回一個負數 * 3、相等則返回0 */ public static int compareAppVersion(String version1, String version2) { if (version1 == null || version2 == null) { throw new RuntimeException("版本號不能為空"); } // 注意此處為正則匹配,不能用. String[] versionArray1 = version1.split("\\."); String[] versionArray2 = version2.split("\\."); int idx = 0; // 取陣列最小長度值 int minLength = Math.min(versionArray1.length, versionArray2.length); int diff = 0; // 先比較長度,再比較字元 while (idx < minLength && (diff = versionArray1[idx].length() - versionArray2[idx].length()) == 0 && (diff = versionArray1[idx].compareTo(versionArray2[idx])) == 0) { ++idx; } // 如果已經分出大小,則直接返回,如果未分出大小,則再比較位數,有子版本的為大 diff = (diff != 0) ? diff : versionArray1.length - versionArray2.length; return diff; }