1. 程式人生 > 實用技巧 >CF1166E The LCMs Must be Large

CF1166E The LCMs Must be Large

一、題目描述

查詢各個部門當前(dept_manager.to_date='9999-01-01')領導當前(salaries.to_date='9999-01-01')薪水詳情以及其對應部門編號dept_no (注:輸出結果以salaries.emp_no升序排序,並且請注意輸出結果裡面dept_no列是最後一列) CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL, -- '員工編號',
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL, -- '部門編號'
`emp_no` int(11) NOT NULL, -- '員工編號'
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));

答案

SELECT salaries.emp_no,salary,from_date,dept_manager.to_date,dept_no FROM salaries 
INNER JOIN dept_manager ON salaries.emp_no=dept_manager.emp_no
WHERE dept_manager.to_date='9999-01-01' AND salaries.to_date='9999-01-01'
ORDER BY salaries.emp_no;

二、題目描述

查詢所有已經分配部門的員工的last_name和first_name以及dept_no(請注意輸出描述裡各個列的前後順序)
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));

答案

select last_name,first_name,dept_no from employees
inner join dept_emp on employees.emp_no=dept_emp.emp_no