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gson 生成的json字串帶\u003c,\u003d,\u003e的解決方案(gson將實體類轉json)

//實驗1

不能,因為函式只能返回一個值

//實驗2

//實驗2
//利用區域性static變數計算階乘

#include<stdio.h>
long long fac(int n); //函式宣告

int main(){
    int i, n;
    
    printf("Enter n:");
    scanf("%d", &n);
    
    for(i=1; i<=n; ++i)
        printf("%d!=%lld\n", i, fac(i));
        
    return 0;
} 

//函式定義
long long fac(int
n) { static long long p = 1; //在第二次被呼叫時能保持第一次被呼叫的值 printf("p = %lld\n", p); p = p*n; return p; }

//實驗2-2
//練習:區域性static變數特性

#include<stdio.h>
int func(int, int);

int main(){
    int k=4,m=1,p1,p2;
    
    p1 = func(k,m);
    p2 = func(k,m);
    printf("%d,%d\n
",p1,p2); return 0; } int func(int a,int b){ static int m=0,i=2; i += m+1; m = i+a+b; return (m); }

static變數在後一次被呼叫時可以保留前一次被呼叫的值

//實驗3

// 尋找兩個整數之間所有的素數(包括這兩個整數 ),把結果儲存在陣列bb中,函式返回素數的個數
//例如,輸入6和21,則輸出為:7 11 13 17 19.

#include<stdio.h>

#define N 1000
int fun(int n, int
m, int bb[N]) { int i,j,k=0,flag; for(j=n;j<=m;j++) { flag=1; for(i=2;i<j;i++) if(j%i==0) { flag=0; break; } if(flag==1) bb[k++]=j; } return k; } int main(){ int n=0,m=0,i,k,bb[N]; scanf("%d",&n); scanf("%d",&m); for(i=0;i<m-n;i++) bb[i]=0; k=fun(n, m, bb); for(i=0;i<k;i++) printf("%4d",bb[i]); return 0; }

//實驗4

//實驗4
#include<stdio.h>
long long fun(int n);

int main(){
    int n;
    long long f;
    
    while(scanf("%d", &n) != EOF) {
        f = fun(n);
        printf("n = %d, f = %lld\n",n,f);
    }
    
    return 0;
} 

long long fun(int n){
    if( n<33 && n>0){
        int j;
        long long sum;
        long long count = 1.0;
        for(j=0;j<n;j++){
            count = count*2;
        }
        sum = count - 1;
        return sum;
    } else
        printf("not quadratic equation.\n");
}

//實驗5

//實驗5
#include<stdio.h>

void draw(int n, char symbol);

#include<stdio.h>
int main(){
    int n, symbol;
    
    while(scanf("%d %c", &n, &symbol) != EOF) {
        draw(n, symbol);
        printf("\n");
    }
    
    return 0;
} 

void draw(int n, char symbol){
    int line = 1;
    int count,c,m;
    c = line;
    m = line;
    
    for(count=0;count<n;count++){
        c = line;
        while(c<n){
            printf(" ");
            c++;
        }
        m = 1;
        while(m<=2*line-1){
            printf("%c",symbol);
            m++;
        }
        printf("\n");
        line++;
    }
}