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des資料加密的python實現

技術標籤:python密碼學

這個學期學習了密碼學,在老師的指導下實現了des資料加密程式碼如下,等有空了再補說明

class des(object):
    """DES加密器
    該類可實現字串的加密與解密
    """

    # 初始化函式
    def __init__(self):
        """初始化方法
        函式有:
        private(非必要請勿使用):
        1.移位函式_Shift(self,s, n)
        2.異或函式_Xor(self,a, b)
        3.明文字串轉二進位制_Get_Bin(self,Texts)
        4.密文字串轉二進位制_Get_bin(self,Texts)
        5.二進位制轉字元函式_Bin_Str(self,s)
        6.十進位制轉二進位制_Ten_To_Two(self,n)
        7.PC置換_PC(self,s, flag)
        8.金鑰生成器_Get_Sk(self)
        9.獲取明文字串_Get_Plaintext(self)
        10.獲取密文字串_Get_Ciphertext(self)
        11.s盒中取數函式_Get_S(self,h, l, n)
        12.P置換_Exchange_P(self,A)
        13.f函式_Function(self,R, K)
        14.IP置換_Exchange_IP(self,s, n)
        public:
        15.加密函式Encryption(self)
        16.解密函式Dencryption(self)
        17.以數字形式展示ShowC_in_num(self,n)
        18.明文以文字形式展示Show_Text(self,flag)
        19.密文以文字形式展示Show_text(self,flag)
        變數:
        1.金鑰self.__Key
        2.明文self.__Plaintext
        3.密文self.__Ciphertext
        """
# 移位函式 def shift(self, s, n): '''s:需要移位的字串 n:需要移動的位數 ''' return s[n:] + s[:n] # 異或函式 def xor(self, a, b): """異或函式 a,b:等長的字串 return:a和b異或後的結果 """ t = zip(a, b) s = [(int
(i) + int(j)) % 2 for i, j in t] S = '' for i in s: S = S + str(i) return S # 明文字串轉二進位制 def get_p_bin(self, Texts): """字串轉二進位制 Text:字串 return 字串對應的二進位制的編碼 """ Text_bin = '' for text in
Texts: s = ord(text) s_bin = '{:016b}'.format(s) Text_bin = Text_bin + s_bin return Text_bin # 密文字串轉二進位制 def get_c_bin(self, Texts): """字串轉二進位制 Text:字串 return 字串對應的二進位制的編碼 """ Text_bin = '' for text in Texts: s = ord(text) s_bin = '{:08b}'.format(s) Text_bin = Text_bin + s_bin return Text_bin # 二進位制轉字元函式 def bin_str(self, s): '''獲取16位的01串,返回對應的漢字''' try: return chr(int(s, 2)) except: return -1 # 十進位制轉二進位制 def ten_to_two(self, n): """返回小於16的數轉換為四位二進位制數(字串) n:小於16的十進位制數 return:四位的二進位制數,不足四位在前方補零 """ n2 = bin(n)[2:] num = len(bin(n)[2:]) if num >= 4: return n2 for i in range(4 - num): n2 = '0' + n2 return n2 # PC置換 def pc(self, s, flag): PC1 = [57, 49, 41, 33, 25, 17, 9, \ 1, 58, 50, 42, 34, 26, 18, \ 10, 2, 59, 51, 43, 35, 27, \ 19, 11, 3, 60, 52, 44, 36, \ 63, 55, 47, 39, 31, 23, 15, \ 7, 62, 54, 46, 38, 30, 22, \ 14, 6, 61, 53, 45, 37, 29, \ 21, 13, 5, 28, 20, 12, 4] PC2 = [14, 17, 11, 24, 1, 5, 3, 28, \ 15, 6, 21, 10, 23, 19, 12, 4, \ 26, 8, 16, 7, 27, 20, 13, 2, \ 41, 52, 31, 37, 47, 55, 30, 40, \ 51, 45, 33, 48, 44, 49, 39, 56, \ 34, 53, 46, 42, 50, 36, 29, 32] S = '' if flag == 1: for i in PC1: S = S + s[i - 1] if flag == 2: for i in PC2: S = S + s[i - 1] return S # 金鑰生成器 def get_sk(self, text): # 獲取金鑰 shift_num = [1, 1, 2, 2, 2, 2, 2, 2, 1, 2, 2, 2, 2, 2, 2, 1] k = text # 請輸入金鑰(四個漢字) k_bin = self.get_p_bin(k) k_bin = self.pc(k_bin, 1) # PC_1置換 K = [] # print('k_bin=',k_bin) num = 0 for i in range(16): num = num + 1 k_bin = self.shift(k_bin[:28], shift_num[i]) + self.shift(k_bin[28:], shift_num[i]) # 分組移位 K.append(self.pc(k_bin, 2)) # PC_2置換,並記錄 if num >= 4: continue self.__key = K # 獲取明文字串 def get_plaintext(self, text): """獲取需要加密的明文並換成二進位制形式""" m = text m_bin = [] M = self.get_p_bin(m) flag = 0 i = 0 for i in range(int(len(M) / 64)): # 四字一組 m_bin.append(M[64 * i:64 * (1 + i)]) flag = 1 i = i if len(M) > 64: m_bin.append(M[64 * (1 + i):] + (64 - len(M[64 * (1 + i):])) * '0') # 字多於於四個時,末位不足四位 elif len(M) < 64: m_bin.append(M + (64 - len(M)) * '0') # 字少於四個時 return m_bin # 返回二進位制程式碼列表 # 獲取密文字串 def get_ciphertext(self, text, flag): m = text m_bin = [] M = '' if flag == 0: M = self.get_c_bin(m) elif flag == 2: for i in text.split(' ')[:-1]: if len(i) < 8: M = M + '0' * (16 - len(i)) + i else: M = M + i elif flag == 16: for i in text.split(' ')[:-1]: if len(bin(int(i, 16))[2:]) < 8: M = M + '0' * (8 - len(bin(int(i, 16))[2:])) + bin(int(i, 16))[2:] else: M = M + bin(int(i, 16))[2:] flag = 0 for i in range(int(len(M) / 64)): # 四字一組 m_bin.append(M[64 * i:64 * (1 + i)]) flag = 1 if len(M) % 64 > 0: m_bin.append(M[64 * (1 + i):] + (64 - len(M[64 * (1 + i):])) * '0') # 字多於於四個時,末位不足四位 elif flag == 0: m_bin.append(M + (64 - len(M)) * '0') # 字少於四個時 return m_bin # 返回二進位制程式碼列表flag # s盒中取數函式 def get_s(self, h, l, n): '''獲取s盒中的數 h:行 l:列 n:第n+1個盒 返回指定s盒的第h行第j列的數 ''' s1 = [14, 4, 13, 1, 2, 15, 11, 8, 3, 10, 6, 12, 5, 9, 0, 7, \ 0, 15, 7, 4, 14, 2, 13, 1, 10, 6, 12, 11, 9, 5, 3, 8, \ 4, 1, 14, 8, 13, 6, 2, 11, 15, 12, 9, 7, 3, 10, 5, 0, \ 15, 12, 8, 2, 4, 9, 1, 7, 5, 11, 3, 14, 10, 0, 6, 13] s2 = [15, 1, 8, 14, 6, 11, 3, 4, 9, 7, 2, 13, 12, 0, 5, 10, \ 3, 13, 4, 7, 15, 2, 8, 14, 12, 0, 1, 10, 6, 9, 11, 5, \ 0, 14, 7, 11, 10, 4, 13, 1, 5, 8, 12, 6, 9, 3, 2, 15, \ 13, 8, 10, 1, 3, 15, 4, 2, 11, 6, 7, 12, 0, 5, 14, 9] s3 = [10, 0, 9, 14, 6, 3, 15, 5, 1, 13, 12, 7, 11, 4, 2, 8, \ 13, 7, 0, 9, 3, 4, 6, 10, 2, 8, 5, 14, 12, 11, 15, 1, \ 13, 6, 4, 9, 8, 15, 3, 0, 11, 1, 2, 12, 5, 10, 14, 7, \ 1, 10, 13, 0, 6, 9, 8, 7, 4, 15, 14, 3, 11, 5, 2, 12] s4 = [7, 13, 14, 3, 0, 6, 9, 10, 1, 2, 8, 5, 11, 12, 4, 15, \ 13, 8, 11, 5, 6, 15, 0, 3, 4, 7, 2, 12, 1, 10, 14, 9, \ 10, 6, 9, 0, 12, 11, 7, 13, 15, 1, 3, 14, 5, 2, 8, 4, \ 3, 15, 0, 6, 10, 1, 13, 8, 9, 4, 5, 11, 12, 7, 2, 14] s5 = [2, 12, 4, 1, 7, 10, 11, 6, 8, 5, 3, 15, 13, 0, 14, 9, \ 14, 11, 2, 12, 4, 7, 13, 1, 5, 0, 15, 10, 3, 9, 8, 6, \ 4, 2, 1, 11, 10, 13, 7, 8, 15, 9, 12, 5, 6, 3, 0, 14, \ 11, 8, 12, 7, 1, 14, 2, 13, 6, 15, 0, 9, 10, 4, 5, 3] s6 = [12, 1, 10, 15, 9, 2, 6, 8, 0, 13, 3, 4, 14, 7, 5, 11, \ 10, 15, 4, 2, 7, 12, 9, 5, 6, 1, 13, 14, 0, 11, 3, 8, \ 9, 14, 15, 5, 2, 8, 12, 3, 7, 0, 4, 10, 1, 13, 11, 6, \ 4, 3, 2, 12, 9, 5, 15, 10, 11, 14, 1, 7, 6, 0, 8, 13] s7 = [4, 11, 2, 14, 15, 0, 8, 13, 3, 12, 9, 7, 5, 10, 6, 1, \ 13, 0, 11, 7, 4, 9, 1, 10, 14, 3, 5, 12, 2, 15, 8, 6, \ 1, 4, 11, 13, 12, 3, 7, 14, 10, 15, 6, 8, 0, 5, 9, 2, \ 6, 11, 13, 8, 1, 4, 10, 7, 9, 5, 0, 15, 14, 2, 3, 12] s8 = [13, 2, 8, 4, 6, 15, 11, 1, 10, 9, 3, 14, 5, 0, 12, 7, \ 1, 15, 13, 8, 10, 3, 7, 4, 12, 5, 6, 11, 0, 14, 9, 2, \ 7, 11, 4, 1, 9, 12, 14, 2, 0, 6, 10, 13, 15, 3, 5, 8, \ 2, 1, 14, 7, 4, 10, 8, 13, 15, 12, 9, 0, 3, 5, 6, 11] if n == 0: return s1[h * 16 + l] if n == 1: return s2[h * 16 + l] if n == 2: return s3[h * 16 + l] if n == 3: return s4[h * 16 + l] if n == 4: return s5[h * 16 + l] if n == 5: return s6[h * 16 + l] if n == 6: return s7[h * 16 + l] if n == 7: return s8[h * 16 + l] # P置換 def exchange_p(self, a): """對得到的資料進行P置換 A:需要進行P置換的字串 return 進行P置換後的字串 """ p = [16, 7, 20, 21, 29, 12, 28, 17, \ 1, 15, 23, 26, 5, 18, 31, 10, \ 2, 8, 24, 14, 32, 27, 3, 9, \ 19, 13, 30, 6, 22, 11, 4, 25] f = '' for i in p: f = f + a[i - 1] return f # f函式 def function(self, r, k): """f函式""" # 擴張函式 e = [32, 1, 2, 3, 4, 5, \ 4, 5, 6, 7, 8, 9, \ 8, 9, 10, 11, 12, 13, \ 12, 13, 14, 15, 16, 17, \ 16, 17, 18, 19, 20, 21, \ 20, 21, 22, 23, 24, 25, \ 24, 25, 26, 27, 28, 29, \ 28, 29, 30, 31, 32, 1] r_e = '' # 初始化擴張後R for i in e: r_e = r_e + r[i - 1] s = self.xor(r_e, k) # 通過s盒進行壓縮 f = '' for i in range(8): h = int(s[0 + 6 * i]) * 2 + int(s[5 + 6 * i]) # 行 l = int(s[1 + 6 * i]) * 8 + int(s[2 + 6 * i]) * 4 + int(s[3 + 6 * i]) * 2 + int(s[4 + 6 * i]) # 列 f = f + self.ten_to_two(self.get_s(h, l, i)) # 置換P f_p = self.exchange_p(f) return f_p # IP置換 def exchange_ip(self, s, n): """IP置換 S:需要置換的字串 n:置換引數,0為初始置換,1為逆初始置換 return :進行置換後的字串 """ ip = [58, 50, 42, 34, 26, 18, 10, 2, \ 60, 52, 44, 36, 28, 20, 12, 4, \ 62, 54, 46, 38, 30, 22, 14, 6, \ 64, 56, 48, 40, 32, 24, 16, 8, \ 57, 49, 41, 33, 25, 17, 9, 1, \ 59, 51, 43, 35, 27, 19, 11, 3, \ 61, 53, 45, 37, 29, 21, 13, 5, \ 63, 55, 47, 39, 31, 23, 15, 7] ip_ = [40, 8, 48, 16, 56, 24, 64, 32, \ 39, 7, 47, 15, 55, 23, 63, 31, \ 38, 6, 46, 14, 54, 22, 62, 30, \ 37, 5, 45, 13, 53, 21, 61, 29, \ 36, 4, 44, 12, 52, 20, 60, 28, \ 35, 3, 43, 11, 51, 19, 59, 27, \ 34, 2, 42, 10, 50, 18, 58, 26, \ 33, 1, 41, 9, 49, 17, 57, 25] S = '' if n == 0: for i in ip: S = S + s[i - 1] if n == 1: for i in ip_: S = S + s[i - 1] return S # 加密函式 def encryption(self, text): key = self.__key c = [] # 密文 self.__plaintext = self.get_plaintext(text) for m in self.__plaintext: m = self.exchange_ip(m, 0) # ip置換 L = m[:32] R = m[32:] for j in range(16): # 16輪迭代 T = L L = R R = self.xor(T, self.function(R, key[j])) c.append(self.exchange_ip(R + L, 1)) self.__ciphertext = c return c # 解密函式 def dencryption(self, text, flag): """"flag=0為字串,flag=2為二進位制串,flag=16為十六進位制""" key = self.__key M = [] # 譯文容器 self.__ciphertext = self.get_ciphertext(text, flag) for m in self.__ciphertext: m = self.exchange_ip(m, 0) # ip置換 L = m[:32] R = m[32:] for j in range(16): # 16輪迭代 T = L L = R R = self.xor(T, self.function(R, key[15 - j])) M.append(self.exchange_ip(R + L, 1)) self.__plaintext = M return M # 以數字形式展示 def showc_in_num(self, n): ''''n代表進位制,目前僅支援2進位制和16進位制''' cstr = '' s_hex = '' for i in self.__ciphertext: cstr = cstr + i if n == 2: for i in range(int(len(cstr) / 8)): s_hex = s_hex + cstr[8 * i:8 + 8 * i] + ' ' return s_hex elif n == 16: s_hex = '' for i in range(int(len(cstr) / 8)): s_hex = s_hex + str(hex(int(cstr[8 * i:8 + 8 * i], 2))) + ' ' return s_hex else: return '請期待後續版本,感謝您的信賴' # 明文以文字形式展示 def show_mtext(self): '''明文''' M = self.__plaintext m_text = '' for text in M: for i in range(4): if text[i * 16:16 * (1 + i)] != '0' * 16: m_text = m_text + self.bin_str(text[i * 16:16 * (1 + i)]) return m_text # 密文以文字形式展示 def show_ctext(self): '''密文''' M = self.__ciphertext m_text = '' for text in M: for i in range(8): m_text = m_text + self.bin_str(text[i * 8:8 * (1 + i)]) return m_text if __name__ == '__main__': key = '塞德里克' D = des() D.get_sk(key) text = '面朝大海,春暖花開!' D.encryption(text) c = D.show_ctext() print('密文:',c) D.dencryption(c,0) m = D.show_mtext() print('明文:',m)

結果
在這裡插入圖片描述