Pandas中兩個dataframe的交集和差集的示例程式碼
阿新 • • 發佈:2020-12-14
建立測試資料:
import pandas as pd import numpy as np #Create a DataFrame df1 = { 'Subject':['semester1','semester2','semester3','semester4','semester1','semester3'],'Score':[62,47,55,74,31,77,85]} df2 = { 'Subject':['semester1','semester4'],'Score':[90,85,74]} df1 = pd.DataFrame(df1,columns=['Subject','Score']) df2 = pd.DataFrame(df2,'Score']) print(df1) print(df2)
執行結果:
求兩個dataframe的交集
intersected_df = pd.merge(df1,df2,how='inner') print(intersected_df)
也可以指定求交集的列:
intersected_df = pd.merge(df1,on=['Subject'],how='inner') print(intersected_df)
求差集
df2-df1:
set_diff_df = pd.concat([df2,df1,df1]).drop_duplicates(keep=False) print(set_diff_df)
df1-df2:
set_diff_df = pd.concat([df1,df2]).drop_duplicates(keep=False) print(set_diff_df)
另一種求差集的方法是:
以df1-df2為例:
df1 = df1.append(df2) df1 = df1.append(df2) set_diff_df = df1.drop_duplicates(subset=['Subject','Score'],keep=False) print(set_diff_df)
得到的df1-df2結果是一樣的:
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