本文例項為大家分享了python實現四人制撲克牌遊戲的具體程式碼，供大家參考，具體內容如下

題目：

設計一個簡單的四人制撲克牌遊戲，能夠完成以下功能：

1. 洗牌
2. 發牌
3.自定義規則，在每輪單張出牌時，判定贏家
4.自定義規則，判定最終的贏家

規則簡化版：

僅能出單張牌，且出牌時，每個人出的是自己手中牌中剛好能壓過上家的最小牌，最先出完的為贏家

import random
from random import choice
flower = ['\u2660','\u2663','\u2665','\u2666']
pai = ['3','4','5','6','7','8','9','10','J','Q','K','A','2']
list = []
list0 = []#儲存發的牌
list1 = []
list2 = []
list3 = []
value = []
value0 = []#儲存牌代表的值
value1 = []
value2 = []
value3 = []
l00 = []#儲存進行升序排序後的牌
l11 = []
l22 = []
l33 = []
for i in flower:
  for j in pai:
    list.append(i+j)
for i in range(4):
  for j in range(13):
    value.append(j)
d = dict(zip(list,value))
for i in range(13):
  for j in range(4):
    if(j == 0):
      k = choice(list)#隨機選牌
      for x in range(len(list)):
        if(k == list[x]):#和連結串列的牌進行匹配，刪掉對應項
          value0.append(d[k])
          list.pop(x)
          break
      list0.append(k)
    if(j == 1):
      k = choice(list)
      for x in range(len(list)):
        if (k == list[x]):
          value1.append(d[k])
          list.pop(x)
          break
      list1.append(k)
    if (j == 2):
      k = choice(list)
      for x in range(len(list)):
        if (k == list[x]):
          value2.append(d[k])
          list.pop(x)
          break
      list2.append(k)
    if (j == 3):
      k = choice(list)
      for x in range(len(list)):
        if (k == list[x]):
          value3.append(d[k])
          list.pop(x)
          break
      list3.append(k)
d0 = dict(zip(list0,value0))#將每個人的牌轉換為字典形式
d1 = dict(zip(list1,value1))
d2 = dict(zip(list2,value2))
d3 = dict(zip(list3,value3))
l0 = sorted(d0.values())#對牌所代表的數字進行排序
l1 = sorted(d1.values())
l2 = sorted(d2.values())
l3 = sorted(d3.values())
#對發給每個人的牌進行排序
for i in range(len(l0)):
  for j in list0:
    if(l0[i] == d0[j]):
      l00.append(j)
      break
for i in range(len(l1)):
  for j in list1:
    if(l1[i] == d1[j]):
      l11.append(j)
      break
for i in range(len(l2)):
  for j in list2:
    if(l2[i] == d2[j]):
      l22.append(j)
      break
for i in range(len(l0)):
  for j in list3:
    if(l3[i] == d3[j]):
      l33.append(j)
      break
# y = choice(['0','1','2','3'])
print("第一個人的牌：",l00)
print("第二個人的牌：",l11)
print("第三個人的牌：",l22)
print("第四個人的牌：",l33)
y = random.randint(0,3)
if (y == 0):
  y = y + 1
  n = l0[0]
  l0.pop(0)
elif (y == 1):
  y = y + 1
  n = l1[0]
  l1.pop(0)
elif (y == 2):
  y = y + 1
  n = l2[0]
  l2.pop(0)
elif (y == 3):
  y = 0
  n = l3[0]
  l3.pop(0)
for i in range(13):
  if(y == 0):
    for j in range(len(l0)):
      if(l0[j] > n):
        n = l0[j]
        l0.pop(j)
        if(len(l0) != 0 and n >= l1[len(l1)-1] and n >= l2[len(l2)-1] and n >= l3[len(l3)-1]):#判斷是否當前牌中最大牌，若是，則該此人繼續出牌
          n = l0[0]
          l0.pop(0)
        break
    y = y + 1
  if (len(l0) == 0):
    print("贏家：第一個人")
    break
  if(y == 1):
    for j in range(len(l1)):
      if(l1[j] > n):
        n = l1[j]
        l1.pop(j)
        if (len(l1) != 0 and n >= l0[len(l0) - 1] and n >= l2[len(l2) - 1] and n >= l3[len(l3) - 1]):
          n = l1[0]
          l1.pop(0)
        break
    y = y + 1
  if (len(l1) == 0):
    print("贏家：第二個人")
    break
  if(y == 2):
    for j in range(len(l2)):
      if(l2[j] > n):
        n = l2[j]
        l2.pop(j)
        if (len(l2) != 0 and n >= l0[len(l0) - 1] and n >= l1[len(l1) - 1] and n >= l3[len(l3) - 1]):
          n = l2[0]
          l2.pop(0)
        break
    y = y + 1
  if (len(l2) == 0):
    print("贏家：第三個人")
    break
  if (y == 3):
    for j in range(len(l3)):
      if (l3[j] > n):
        n = l3[j]
        l3.pop(j)
        if (len(l3) != 0 and n >= l0[len(l0) - 1] and n >= l1[len(l1) - 1] and n >= l2[len(l2) - 1]):
          n = l3[0]
          l3.pop(0)
        break
    y = 0
  if (len(l3) == 0):
    print("贏家：第四個人")
    break
#將剩餘牌從鍵值轉化成牌
if(len(l0) != 0):
  for i in range(len(l0)):
    for j in list0:
      if(l0[i] == d0[j]):
        l0[i] = j
        break
if(len(l1) != 0):
  for i in range(len(l1)):
    for j in list1:
      if(l1[i] == d1[j]):
        l1[i] = j
        break
if(len(l2) != 0):
  for i in range(len(l2)):
    for j in list2:
      if(l2[i] == d2[j]):
        l2[i] = j
        break
if(len(l3) != 0):
  for i in range(len(l3)):
    for j in list3:
      if(l3[i] == d3[j]):
        l3[i] = j
        break
print("第一個人的牌：",l0)
print("第二個人的牌：",l1)
print("第三個人的牌：",l2)
print("第四個人的牌：",l3)

以上就是本文的全部內容，希望對大家的學習有所幫助，也希望大家多多支援我們。