js獲取連結?後邊的引數名稱或者值,根據url ?後的引數做判斷
阿新 • • 發佈:2020-12-19
技術標籤:jQuery
var url = location.search; //獲取url中"?"符後的字串 ,包括?
console.log(url);
function GetRequest() {
var url = location.search; //獲取url中"?"符後的字串
var theRequest = new Object();
if(url.indexOf("?") != -1) {
var str = url.substr(1);
strs = str.split("&");
for(var i = 0; i < strs.length; i++) {
theRequest[strs[i].split("=")[0]] = unescape(strs[i].split("=")[1]);
}
}
return theRequest;
}
var Request = undefined;
Request = GetRequest();
console.log(Request); //最後獲取的欄位名+值
const keys= Object.keys(Request);
console.log(keys);//陣列
console.log(keys[0]);//輸出a
案例:
設計稿:
根據url後的引數判斷狀態為:已解決,未解決,全部;
var url = location.search; //獲取url中"?"符後的字串 ,包括?
// console.log(url);
function GetRequest() {
var url = location.search; //獲取url中"?"符後的字串
var theRequest = new Object();
if(url.indexOf("?") != -1) {
var str = url.substr(1);
strs = str.split("&");
for(var i = 0; i < strs.length; i++) {
theRequest[strs[i].split("=")[0]] = unescape(strs[i].split("=")[1]);
}
}
return theRequest;
}
var Request = undefined;
Request = GetRequest();
// console.log(Request);//最後獲取的欄位名+值
// const keys= Object.keys(Request);
// console.log(keys);//陣列
// console.log(keys[0]);//輸出a
let status = Request.status;
if(status == 2){
$('.tit05 .tit05div .zhuangtai').text('全部');
}else if(status == 1){
$('.tit05 .tit05div .zhuangtai').text('已解決');
}else{
$('.tit05 .tit05div .zhuangtai').text('未解決');
}
參考文章:
js獲取連結?後邊的引數名稱或者值:https://www.cnblogs.com/zxcc/p/11454196.html