技術標籤：java

題目

返回值和引數的四種組合

解答

package modeal4;

import java.util.Scanner;

public class Duxiang1 {

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		int i, j, age;
		String name, idCard;

		Duxiang1 duxiang1 = new Duxiang1();
		duxiang1.sum();// 通過main方法呼叫
		System.out.
 
println(duxiang1.sum1());// 有返回值時，duxiang1.sum1()為返回值的型別
		Scanner sc = new Scanner(System.in);
		i = sc.nextInt();
		j = sc.nextInt();
		duxiang1.sum2(i, j);// 通過引數呼叫，需要給引數賦值
		name = sc.next();
		age = sc.nextInt();
		idCard = sc.next();
		duxiang1.sum3(name, age, idCard);
		System.out.println(duxiang1.
 
sum3(name, age, idCard));
	}
   //無返回值，無引數
	public void sum() {
		int sum = 0, i;
		for (i = 1; i <= 100; i++) {
			sum = sum + i;
		}
		System.out.println(sum);
	}
	//有返回值，無引數
	public int sum1() {
		int s = 0;
		int i = 1;
		for (; i <= 10; i++) {
			s = s + i;
		}
		return s;//有返回值的要有return
	}
	 //無返回值，有引數
 

	public void sum2(int i, int j) {
		int m = i * j;
		System.out.println(m);
	}
	//有返回值，有引數
	public String sum3(String name, int age, String idCard) {
		String str;
		str = name + "  " + age + "  " + idCard;
		return str;
	}

}