轉置矩陣(Python)
阿新 • • 發佈:2020-12-28
題目:
#方法1
lis = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
count = 0
for i in range(len(lis)):
for j in range(len(lis[i])):
if i > j:
lis[i][j], lis[j][i] = lis[j][i], lis[i][j]
count += 1
print(*lis, sep = '\n')
print(count)
結果:
[1, 4, 7]
[2, 5, 8]
[3, 6, 9]
3
#方法二
lis = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
count = 0
for i, _ in enumerate(lis):
for j, _ in enumerate(lis[i]):
if i > j:
lis[i][j], lis[j][i] = lis[j][i], lis[i][j]
count += 1
print(*lis, sep = '\n')
print(count)
結果:
[1, 4, 7]
[2, 5, 8]
[3, 6, 9]
3
#方法三
lis = [[ 1, 2, 3], [4, 5, 6], [7, 8, 9]]
count = 0
for i in range(len(lis)):
for j in range(i):
lis[i][j], lis[j][i] = lis[j][i], lis[i][j]
count += 1
print(*lis, sep = '\n')
print(count)
結果:
[1, 4, 7]
[2, 5, 8]
[3, 6, 9]
3
二乘三轉置矩陣:
#方法四
lis = [[1, 2, 3], [4, 5, 6]]
list_ = []
for i, row in enumerate(lis):
for j, col in enumerate(row):
if i == 0:
list_.append([])
list_[j].append(col)
print(*list_, sep='\n')
或者
lis = [[1, 2, 3], [4, 5, 6]]
list_ = []
for i, row in enumerate(lis):
for j, col in enumerate(row):
if len(list_) < j + 1:
list_.append([])
list_[j].append(col)
print(*list_, sep='\n')
結果:
[1, 4]
[2, 5]
[3, 6]
方法五
lis = [[1, 2, 3], [4, 5, 6]]
list_ = [[None for i in range(len(lis))] for i in range(len(lis[0]))]
for i in range(len(lis)):
for j in range(len(lis[0])):
list_[j][i] = lis[i][j]
print(*list_, sep='\n')```
結果:
```python
[1, 4]
[2, 5]
[3, 6]