python學習筆記-4.函式基礎
阿新 • • 發佈:2020-12-31
主方法
public static void main(String[] args) { Jedis jedis = new Jedis("localhost", 6379); //測試jedis連線 //System.out.println(jedis.ping()); //排序 testScort(jedis); }
測試程式碼
/*** *@author zh *@Date 2020/12/31 * @param jedis *@return void *@MethodNotes 測試排序 **/ public static void testScort(Jedis jedis){ /*** *@author zh *@Date 2020/12/31 *@MethodNotes 首先生成一個排序物件 * 然後建立兩個用來測試的集合 一個字母的集合,一個數字的集合 * * 測試程式碼 * SortingParams sortingParams = new SortingParams(); 這個就是排序物件 * jedis.lpush("number","1","2","9","100","20","50","3","22","33","77",""); 新增兩個list集合 * jedis.lpush("letter","Adad","Mdsa","Edsa","Bdas","Fdsa","Pdas","adas","Bdas","bdas","cdas","Cdsa","hdas","Hdsa","odas","Oda"); * * 數字升序排列 * List<String> number = jedis.sort("number", sortingParams.asc()); * System.out.println(number); * * 數字降序排列 * List<String> number1 = jedis.sort("number", sortingParams.desc()); * System.out.println(number1); * * 按首字母a-z排序,不過排完之後是一個倒序,大寫字母在棧底,小寫字母棧頭 * List<String> letter = jedis.sort("letter", sortingParams.alpha()); * System.out.println(letter); * **/ }