技術標籤：PAT甲級

1005 Spell It Right (20分)

Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.

Input Specification:

Each input file contains one test case. Each case occupies one line which contains an N (≤10100).

Output Specification:

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

Sample Input:

12345

Sample Output:

one five

~

半年沒寫過Java了，原以為不會寫了，但是竟然可以一遍就寫出來（當然只是最基本的輸入輸出）

幾乎一樣的程式碼，時間確實差的離譜

程式碼_Java

import
 
 java.util.Scanner;
public class a005
{
    public static void main(String []args)
    {
        String str=new String();
        Scanner sc=new Scanner(System.in);
        str=sc.next();
        int cnt=0;
        for(int i=0;i<str.length();++i)
            cnt+=(int)(str.charAt(i)-'0');
        String [
 
] nums={"zero","one","two","three","four","five","six","seven","eight","nine"};
        String tmp=Integer.toString(cnt);
        for(int i=0;i<tmp.length();++i)
        {
            if(i!=0)
                System.out.print(" ");
            System.out.print(nums[tmp.charAt(i)-'0']);
        }

    }
}

程式碼_cpp

#include <iostream>
#include <string>
using namespace std;
int main()
{
    string str;
    cin >> str;
    int cnt = 0;
    for (int i = 0; i < str.size(); ++i)
        cnt += (int)(str[i] - '0');
    string nums[10] = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
    string tmp = to_string(cnt);
    for (int i = 0; i < tmp.length(); ++i)
    {
        if (i != 0)
            cout << " ";
        cout << nums[tmp[i] - '0'];
    }
}