python編寫扎金花小程式
阿新 • • 發佈:2021-01-22
遊戲規則:
一付撲克牌,去掉大小王,每個玩家發3張牌,最後比大小,看誰贏。
有以下幾種牌:
豹子:三張一樣的牌,如3張6.
順金:又稱同花順,即3張同樣花色的順子, 如紅桃 5、6、7
順子:又稱拖拉機,花色不同,但是順子,如紅桃5、方片6、黑桃7,組成的順子
對子:2張牌一樣
單張:單張最大的是A
這幾種牌的大小順序為, 豹子>順金>順子>對子>單張
程式需要實現的點:
-
先生成一付完整的撲克牌
-
給5個玩家隨機發牌
-
統一開牌,比大小,輸出贏家是誰
主要思路:
- 把各種牌用積分來計算,最後加上三張牌的基礎積分。即:最終積分=基礎積分+牌型積分。最後比較最紅積分,誰的積分大,誰排名就靠前。
附上原始碼:
# -*- coding: utf-8 -*-
"""
# @Time : 2021-01-07 14:55
# @author : jianwei
# @Software : PyCharm
"""
import random
import operator
puke = [] # 儲存撲克牌
num_list = ['2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K', 'A']
hua_list = ['梅花', '紅桃', '黑桃' , '方塊']
sotr_dic = {'2': 0, '3': 1, '4': 2, '5': 3, '6': 4, '7': 5, '8': 6, '9': 7, '10': 8, 'J': 9, 'Q': 10, 'K': 11, 'A': 12,
'對子': 15, '順子': 30, '順金': 60, '豹子': 100}
count_new_list = [] # 儲存玩家分數和排序後排名
count_dic = {} # 儲存玩家分數
# 準備52張撲克
for hua in hua_list:
for num in num_list:
a = hua + num
puke.append(a)
player_dic = {'玩家1': [], '玩家2': [], '玩家3': [], '玩家4': [], '玩家5': []}
# 隨機給五個玩家發牌
# print(len(puke))
for key, value in player_dic.items():
for i in range(3):
plate = random.sample(puke, 3)
player_dic[key] = plate
for i in plate:
puke.remove(i)
# print(player_dic)
# 獲取玩家的牌型
def paixing(list1):
num = []
huase = []
for i in list1:
a = i[2:]
b = i[:2]
num.append(a)
huase.append(b)
return num, huase
# 對數字的牌型進行排序
def sotr(num):
new_num = []
sort_list2 = []
list1 = []
for i in num:
new_num.append(sotr_dic[i])
new_num = sorted(new_num)
for new in new_num:
sort_list2.append([k for k, v in sotr_dic.items() if v == new])
for m in sort_list2:
for n in m:
list1.append(n)
return list1
# 對玩家的牌形統計分數
def count(num, huase):
a = 0
base_count = sotr_dic[num[0]] + sotr_dic[num[1]] + sotr_dic[num[2]]
if num[0] == num[1] and num[1] == num[2]:
paixing = '豹子'
a = base_count + sotr_dic[paixing]
# print(paixing, a)
elif (sotr_dic[num[0]] + 1 == sotr_dic[num[1]] and sotr_dic[num[2]] - 1 == sotr_dic[num[1]]) and (huase[0] == huase[
1] and huase[1] == huase[2]):
paixing = '順金'
a = base_count + sotr_dic[paixing]
# print(paixing, a)
elif (sotr_dic[num[0]] + 1 == sotr_dic[num[1]]) and (sotr_dic[num[2]] - 1 == sotr_dic[num[1]]) and (
huase[0] != huase[
1] or huase[1] != huase[2]):
paixing = '順子'
a = base_count + sotr_dic[paixing]
# print(paixing, a)
elif (num[0] == num[1] and num[1] != num[2]) or (num[1] == num[2] and num[0] != num[1]) or (
num[0] == num[2] and num[1] != num[0]):
paixing = '對子'
a = base_count + sotr_dic[paixing]
# print(paixing, a)
else:
a = base_count
return a
# 對儲存玩家分數的字典進行排序
def compare(count_dic):
d = list(zip(count_dic.values(), count_dic.keys()))
return sorted(d, reverse=True)
for key, value in player_dic.items():
# print(key,value)
num, huase = paixing(value)
# print(num,huase)
num = sotr(num)
# print(num, huase)
count1 = count(num, huase)
# print(count1)
count_dic[key] = count1
print(key + "的牌為:" + str(value))
count_new_list = compare(count_dic)
# print(count_new_list)
print('最終排名:' + "\t" + count_new_list[0][1] + "第一名" + "\t" + count_new_list[1][1] + "第二名" + "\t" + count_new_list[2][
1] + "第三名" + "\t" + count_new_list[3][1] + "第四名" + "\t" + count_new_list[4][1] + "第五名")
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