技術標籤：HDUc++演算法

題目連結

#include<iostream>
using namespace std;
int main()
{
    int n, m;
    bool fa;
    while (cin>>n>>m)
    {
        fa = false;
        if (n == 0 && m == 0)break;
        for (int i = -10000 + 1; i < 10000; i++)
        {
            if ((n - i) * i == m)
 

            {
                fa = true;
                break;
            }
        }
        if (fa)
        {
            cout << "Yes" << endl;
        }
        else
        {
            cout << "No" << endl;
        }

    }
    return 0;
}