python程式設計快速上手-實踐專案答案5
阿新 • • 發佈:2021-01-30
Python程式設計快速上手第五章課後答案
好玩遊戲的物品清單
字典值:
{'rope': 1, 'torch': 6, 'gold coin': 42, 'dagger': 1, 'arrow': 12}
寫一個名為displayInventory()的函式,它接受任何可能的物品清單,並顯示如下:
Inventory
1 rope
6 torch
42 gold coin
1 dagger
12 arrow
Total number of items: 62
程式碼如下:
stuff = {'rope': 1, 'torch' : 6, 'gold coin': 42, 'dagger': 1, 'arrow': 12}
def displayInventory(items):
print('Inventory')
total_num = 0
for k, v in items.items():
print(str(v) + ' ' + k)
total_num += v
print('Total number of items: ' + str(total_num))
displayInventory(stuff)
列表到字典的函式,針對好玩遊戲物品清單
寫一個名為addToInventory(inventory,addedItems)的函式,其中inventory引數是一個字典,表示玩家的物品清單,addedItems引數是一個列表。
addToInventory()函式應該返回一個字典,表示更新過的物品清單。請注意,列表可以包含多個一樣的項。
輸出應如下:
Inventory
45 gold coin
1 rope
1 dagger
1 ruby
Total number of items: 48
程式碼如下:
dragonLoot = ['gold coin', 'dagger', 'gold coin', 'gold coin', 'ruby' ]
def displayInventory(items):
print('Inventory')
total_num = 0
for k, v in items.items():
print(str(v) + ' ' + k)
total_num += v
print('Total number of items: ' + str(total_num))
def addToInventory(inventory, addedItem):
for i in addedItem:
if i in inventory:
inventory[i] += 1
else:
inventory[i] = 1
return inventory
inv = {'gold coin': 42, 'rope': 1}
dragonLoot = ['gold coin', 'dagger', 'gold coin', 'gold coin', 'ruby']
inv = addToInventory(inv, dragonLoot)
displayInventory(inv)