多執行緒問題之按序列印
阿新 • • 發佈:2021-02-11
技術標籤:多執行緒
一、題目描述
我們提供了一個類:
public class Foo {
public void first() { print(“first”); }
public void second() { print(“second”); }
public void third() { print(“third”); }
}
三個不同的執行緒 A、B、C 將會共用一個 Foo 例項。
一個將會呼叫 first() 方法
一個將會呼叫 second() 方法
還有一個將會呼叫 third() 方法
請設計修改程式,以確保 second() 方法在 first() 方法之後被執行,third() 方法在 second() 方法之後被執行。示例 1:
輸入: [1,2,3]
輸出: “firstsecondthird”
解釋:
有三個執行緒會被非同步啟動。
輸入 [1,2,3] 表示執行緒 A 將會呼叫 first() 方法,執行緒 B 將會呼叫 second() 方法,執行緒 C 將會呼叫 third() 方法。
正確的輸出是 “firstsecondthird”。
示例 2:
輸入: [1,3,2]
輸出: “firstsecondthird”
解釋:
輸入 [1,3,2] 表示執行緒 A 將會呼叫 first() 方法,執行緒 B 將會呼叫 third() 方法,執行緒 C 將會呼叫 second() 方法。
正確的輸出是 “firstsecondthird”。
二、題解
方法一:使用ReentrantLock
class Foo {
private int number = 1;
private Lock lock = new ReentrantLock();
private Condition condition1 = lock.newCondition();
private Condition condition2 = lock.newCondition();
private Condition condition3 = lock.newCondition();
public Foo() {
number = 1;
}
public void first(Runnable printFirst) throws InterruptedException {
lock.lock();
try{
if(number!=1){
condition1.await();
}
// printFirst() outputs "first". Do not change or remove this line.
printFirst.run();
number = 2;
condition2.signal();
}finally{
lock.unlock();
}
}
public void second(Runnable printSecond) throws InterruptedException {
lock.lock();
try{
if(number != 2){
condition2.await();
}
// printSecond() outputs "second". Do not change or remove this line.
printSecond.run();
number = 3;
condition3.signal();
}finally{
lock.unlock();
}
}
public void third(Runnable printThird) throws InterruptedException {
lock.lock();
try{
if(number != 3)
condition3.await();
// printThird.run() outputs "third". Do not change or remove this line.
printThird.run();
number = 1;
condition1.signal();
}finally{
lock.unlock();
}
}
}
-方法二:使用Atomic
class Foo {
private AtomicInteger firstJobDone = new AtomicInteger(0);
private AtomicInteger secondJobDone = new AtomicInteger(0);
public Foo() {
}
public void first(Runnable printFirst) throws InterruptedException {
// printFirst() outputs "first". Do not change or remove this line.
printFirst.run();
firstJobDone.incrementAndGet();
}
public void second(Runnable printSecond) throws InterruptedException {
while(firstJobDone.get()!=1){
}
// printSecond() outputs "second". Do not change or remove this line.
printSecond.run();
secondJobDone.incrementAndGet();
}
public void third(Runnable printThird) throws InterruptedException {
while(secondJobDone.get()!=1){
}
// printThird.run() outputs "third". Do not change or remove this line.
printThird.run();
}
}