Newtonsoft.Json.Linq 常用方法總結
阿新 • • 發佈:2019-12-31
1、Entity to Json
1.1、準備工作
我們以如下的 Person
類舉例,其中包含了常用的資料型別:
public class Person
{
public int ID { get; set; }
public string Name { get; set; }
public DateTime Birthday { get; set; }
public bool IsVIP { get; set; }
public float Account { get; set; }
public string[] Favorites { get ; set; }
public string Remark { get; set; }
}
複製程式碼
建立一個 Person
例項:
Person person = new Person
{
ID = 1,Name = "張三",Birthday = DateTime.Parse("2000-01-02"),IsVIP = true,Account = 12.34f,Favorites = new string[] { "吃飯","睡覺" }
};
複製程式碼
1.2、Entity to Json
返回不縮排的 Json 字串
JsonConvert.SerializeObject(person)
複製程式碼
返回:
{"ID":1,"Name":"張三","Birthday":"2000-01-02T00:00:00","IsVIP":true,"Account":12.34,"Favorites":["吃飯","睡覺"],"Remark":null}
複製程式碼
返回縮排的 Json 字串
JsonConvert.SerializeObject(person,Formatting.Indented);
複製程式碼
返回:
{
"ID": 1,"Name": "張三","Birthday": "2000-01-02T00:00:00","IsVIP": true,"Account": 12.34,"Favorites": [
"吃飯" ,"睡覺"
],"Remark": null
}
複製程式碼
Json 字串縮排
private string JsonIndentation(string str)
{
//string str = JsonConvert.SerializeObject(entity);
JsonSerializer serializer = new JsonSerializer();
TextReader tr = new StringReader(str);
JsonTextReader jtr = new JsonTextReader(tr);
object obj = serializer.Deserialize(jtr);
if (obj != null)
{
StringWriter textWriter = new StringWriter();
JsonTextWriter jsonWriter = new JsonTextWriter(textWriter)
{
Formatting = Formatting.Indented,Indentation = 4,IndentChar = ' '
};
serializer.Serialize(jsonWriter,obj);
return textWriter.ToString();
}
else
{
return str;
}
}
複製程式碼
或者:
private string JsonIndentation(string json)
{
JObject obj = JObject.Parse(json);
return obj.ToString();
}
複製程式碼
其他設定
JsonSerializerSettings settings = new JsonSerializerSettings();
// 設定日期格式
settings.DateFormatString = "yyyy-MM-dd";
// 忽略空值
settings.NullValueHandling = NullValueHandling.Ignore;
// 縮排
settings.Formatting = Formatting.Indented;
JsonConvert.SerializeObject(person,settings);
複製程式碼
返回:
{
"ID": 1,"Birthday": "2000-01-02","Favorites": [
"吃飯","睡覺"
]
}
複製程式碼
1.3、Json to Entity
JsonConvert.DeserializeObject<Person>(json);
複製程式碼
2、Linq To Json
2.1、建立物件
JObject obj = new JObject();
obj.Add("ID",1);
obj.Add("Name","張三");
obj.Add("Birthday",DateTime.Parse("2000-01-02"));
obj.Add("IsVIP",true);
obj.Add("Account",12.34f);
// 建立陣列
JArray array = new JArray();
array.Add(new JValue("吃飯"));
array.Add(new JValue("睡覺"));
obj.Add("Favorites",array);
obj.Add("Remark",null);
複製程式碼
2.2、從 Json 字串建立 JObject
string json = "{\"ID\":1,\"Name\":\"張三\",\"Birthday\":\"2000-01-02T00:00:00\",\"IsVIP\":true,\"Account\":12.34,\"Favorites\":[\"吃飯\",\"睡覺\"],\"Remark\":null}";
JObject obj = JObject.Parse(json);
複製程式碼
2.3、從 Entity 建立 JObject
JObject obj = JObject.FromObject(person);
複製程式碼
用匿名物件建立 JObject
JObject obj = JObject.FromObject(new { name = "jack",age = 18 });
複製程式碼
顯示:
{
"name": "jack","age": 18
}
複製程式碼
2.2、獲取值
int id;
if (obj["ID"] != null)
id = obj["ID"].Value<int>();
複製程式碼
獲取陣列
Newtonsoft.Json.Linq 不支援直接獲取陣列,但是可以獲取 List
,然後再轉化為陣列。
string[] favorites;
if (obj["Favorites"] != null)
favorites = obj["Favorites"].Value<List<string>>().ToArray();
複製程式碼