自定義form post提交
阿新 • • 發佈:2021-06-02
var myPost = function(url,args,ajax_form_options){ var body = $(document.body),form = $("<form method='post'></form>"),input; form.attr({"action":url}); for(var key in args){ input = $("<input type='hidden'>"); input.attr({"name":key}); input.val(args[key]); form.append(input); } form.appendTo(document.body); form.ajaxSubmit(ajax_form_options); document.body.removeChild(form[0]); } var ajax_form_options = { success : function(data) { //成功的回撥函式 } } var url = '/xxx/xxx/xxx'; var param = {'xxx' : xxx}; myPost(url,param,ajax_form_options); 需要引入jquery-1.7.2.min.js和jquery-form.js
轉載於:https://my.oschina.net/kdy1994/blog/994255