1. 程式人生 > 其它 >死鎖與死鎖的解決程式碼

死鎖與死鎖的解決程式碼

Given an integer arraynumsand an integerk, returntrueif it is possible to divide this array intoknon-empty subsets whose sums are all equal.

Example 1:

Input: nums = [4,3,2,3,5,2,1], k = 4
Output: true
Explanation: It's possible to divide it into 4 subsets (5), (1, 4), (2,3), (2,3) with equal sums.

Example 2:

Input: nums = [1,2,3,4], k = 3
Output: false

Constraints:

  • 1 <= k <= nums.length <= 16
  • 1 <= nums[i] <= 104
  • The frequency of each element is in the range[1, 4].
class Solution {
    public boolean canPartitionKSubsets(int[] nums, int k) {
        if(nums.length < k) return
false; int sum = 0; for(int i : nums) sum += i; if(sum % k != 0) return false; boolean[] visited = new boolean[nums.length]; return dfs(visited, nums, 0, 0, sum / k, k); } public boolean dfs(boolean[] visited, int[] nums, int start, int cur, int target, int
k) { if(k == 0) return true; if(cur == target) return dfs(visited, nums, 0, 0, target, k - 1); for(int i = start; i < nums.length; i++) { if(visited[i] || cur + nums[i] > target) continue; visited[i] = true; if(dfs(visited, nums, i + 1, cur + nums[i], target, k)) return true; visited[i] = false; } return false; } }