This time you are asked to tell the difference between the lowest grade of all the male students and the highest grade of all the female students.

Input Specification:

Each input file contains one test case. Each case contains a positive integerN, followed byNlines of student information. Each line contains a student'sname

Output Specification:

For each test case, output in 3 lines. The first line gives the name and ID of the female student with the highest grade, and the second line gives that of the male student with the lowest grade. The third line gives the differencegrade​F​​−grade​M​​. If one such kind of student is missing, outputAbsent

Sample Input 1:

3
Joe M Math990112 89
Mike M CS991301 100
Mary F EE990830 95

Sample Output 1:

Mary EE990830
Joe Math990112
6

Sample Input 2:

1
Jean M AA980920 60

Sample Output 2:

Absent
Jean AA980920
NA
思路：同1006題，不過要注意性別
AC程式碼：

#include<bits/stdc++.h>
using
 
 namespace std;
const int maxn=10010;
typedef struct students{
    string name;
    char gender;
    string id;
    int grade;
}stu;
int main(){
    stu st[maxn];
    int n;
    cin>>n;
    int highF=-1;
    int minM=101;
    int insF=-1,insM=-1;
    for(int i=0;i<n;i++){
        cin>>st[i].name;
        cin>>st[i].gender;
        cin>>st[i].id;
        cin>>st[i].grade;
        if(st[i].gender=='F'&&st[i].grade>highF){
            highF=st[i].grade;
            insF=i;
        }
        if(st[i].gender=='M'&&st[i].grade<minM){
            minM=st[i].grade;
            insM=i;
        }
    }
    if(insF!=-1){
        cout<<st[insF].name<<" "<<st[insF].id<<endl;
    }
    else{
        cout<<"Absent"<<endl;
    }
    if(insM!=-1){
        cout<<st[insM].name<<" "<<st[insM].id<<endl;
    }
    else{
        cout<<"Absent"<<endl;
    }
    if(insF==-1||insM==-1){
        cout<<"NA"<<endl;
    }
    else{
        cout<<highF-minM<<endl;
    }
    
    return 0;
}