js刪除物件中的某一個欄位的方法
阿新 • • 發佈：2021-07-02
方法一:不改變原來物件
let item = {
name:'張三',
age:'18',
gender:'男'
};
console.log(item)// {age: "18",gender: "男",name: "張三"}
let { age,...params } = item;
console.log(item)// {age: "18",gender: "男",name: "張三"}
console.log(typeofparams.age)// undefined
console.log(params)// {gender: "男",name: "張三"}
方法二:直接改變物件
let item1 = {name:'張三',
age:'18',
gender:'男'
};
console.log(item1)// {age: "18",gender: "男",name: "張三"}
deleteitem1.name;
console.log(typeofitem1.name)// undefined
console.log(item1)// // {age: "18",gender: "男"}