java運算子之位運算
阿新 • • 發佈:2021-07-28
package operator; public class Demo03 { public static void main(String[] args) { text(); text2(); text3(); } public static void text3(){ //位運算 /* A = 0011 1100 B = 0000 1101 A&B(A與B) =0000 1100 A|B(A或B) =0011 1101 A^B(異或) =0011 0001 相同為0 不同為1 ~B(取反) =1111 0010 2*8=16 <<(左移) *2 >>(右移) /2 0000 0000 0 0000 0001 1 0000 0010 2 0000 0011 3 0000 0100 4 0000 1000 8 0001 0000 16 * */ System.out.println("2<<3:==》"+(2<<3)); } public static void text(){ //短路運算 int a=5; boolean b=(a<4)&&(a++<4); System.out.println(a);//5 System.out.println(b);//false } public static void text2(){ boolean a=true; boolean b=false; System.out.println("a && b:\t"+(a&&b));//false System.out.println("a || b:\t"+(a||b));//true System.out.println("!a && b:\t"+!(a&&b));//true } }