四則運算第三部
阿新 • • 發佈：2021-09-20
程式碼：
packageJava one;
importjava.util.*;
publicclasssizeyunsuan {
publicstaticint[] randomCommon(intn,intmin,intmax){
/* if (n > (max - min + 1) || max < min) {
return null;
}*/
int[] result =newint[n];
intcount =0;
while(count < n) {
intnum = (int) (Math.random() * (max - min)) + min;
booleanflag =true;
for(intj =0; j < n; j++) {
if(num == result[j]){
flag =false;
break;
}
}
if(flag){
result[count] = num;
count++;
}
}
returnresult;
}
publicstaticchard(intpanduan){
Random r =newRandom();
intyunsuanfu= r.nextInt(100);
charfh=' ';
if(panduan==1)
{
switch(yunsuanfu%4)
{
case0:fh='+';break;
case1:fh='-';break;
case2:fh='*';break;
case3:fh='/';break;
}
}
elseif(panduan==2)
{
switch(yunsuanfu%2)
{
case0:fh='+';break;
case1:fh='-';break;
}
}
returnfh;
}
publicstaticvoidmain(String[] args) {
System.out.println("請輸入題目個數:");
Scanner input =newScanner(System.in);
intnum=input.nextInt();
System.out.println("請輸入操作個數（1.兩個 2.三個）");
intczs=input.nextInt();
System.out.println("請輸入數值範圍：");
inta=input.nextInt();
intb=input.nextInt();
if((b-a)<num*(czs+1))
{
System.out.println("系統崩潰！");
System.exit(0);
}
System.out.println("是否需要乘除運算（1.是 2.否）");
intcc=input.nextInt();
Random r =newRandom();
intx,y,z;
if(czs==1)
{
int[]arr1 =randomCommon(num*2,a,b);
for(inti=0;i<num*2;i++)
{
x=arr1[i];
y=arr1[i+1];
i++;
System.out.println(""+x+d(cc)+y+"=");
}
}
elseif(czs==2)//加括號
{
System.out.println("是否需要括號運算（1.是 2.否）");
intkh=input.nextInt();
int[]arr2 =randomCommon(num*3,a,b);
for(inti=0;i<num*3;i++)
{
x=arr2[i];
y=arr2[i+1];
z=arr2[i+2];
i+=2;
if(kh==1)
{
intkuohao= r.nextInt(99);
switch(kuohao%2)
{
case0:System.out.println("("+x+d(cc)+y+")"+d(cc)+z+"=");break;
case1:System.out.println(""+x+d(cc)+"("+y+d(cc)+z+")=");break;
}
}
elseif(kh==2)
{
System.out.println(""+x+d(cc)+y+d(cc)+z+"=");
}
input.close();
}
}
}
}