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在Spring原始碼專案中建立使用Springmvc功能模組

  1 #1.查詢工資最低的員工資訊:last name, salary
  2 SELECT
  3     last_name,
  4     salary
  5 FROM
  6     employees
  7 WHERE
  8     salary = (
  9         SELECT
 10             MIN(salary)
 11         FROM
 12             employees
 13     );
 14 
 15 #2.查詢平均工資最低的部門資訊
 16 SELECT
 17     *
 18 FROM
 19     departments
20 WHERE 21 department_id = ( 22 SELECT 23 department_id 24 FROM 25 employees 26 GROUP BY 27 department_id 28 ORDER BY 29 avg(salary) 30 LIMIT 1 31 ); 32 33 #3.查詢平均工資最低的部門資訊和該部門的平均工資 34 #①各部門的平均工資
35 SELECT 36 avg(salary), 37 department_id 38 FROM 39 employees 40 GROUP BY 41 department_id #②求出最低平均工資的部門編號 42 SELECT 43 avg(salary), 44 department_id 45 FROM 46 employees 47 GROUP BY 48 department_id 49 ORDER BY 50 avg
(salary) 51 LIMIT 1; 52 53 #③查詢部門資訊 54 SELECT 55 d.*, ag 56 FROM 57 departments d 58 JOIN ( 59 SELECT 60 avg(salary), 61 department_id 62 FROM 63 employees 64 GROUP BY 65 department_id 66 ORDER BY 67 avg(salary) 68 LIMIT 1 69 ) ag_dep ON d.department_id = ag_dep.department_id #4.查詢平均工資最高的job資訊 70 SELECT 71 avg(salary) 72 FROM 73 employees 74 GROUP BY 75 job_id 76 ORDER BY 77 avg(salary) DESC 78 LIMIT 1 ②查詢job資訊 SELECT 79 * 80 FROM 81 jobs 82 WHERE 83 job_id = ( 84 SELECT 85 job_id 86 FROM 87 employees 88 GROUP BY 89 job_id 90 ORDER BY 91 avg(salary) DESC 92 LIMIT 1 93 ); 94 95 #5.查詢平均工資高於公司平均工資的部門有哪些? 96 SELECT 97 avg(salary), 98 department_id 99 FROM 100 employees 101 GROUP BY 102 department_id; 103 104 105 HAVING 106 avg(salary) > ( 107 SELECT 108 avg(salary) 109 FROM 110 employees 111 ); 112 113 #6.查詢出公司中所有 manager的詳細資訊 114 SELECT 115 * 116 FROM 117 employees 118 WHERE 119 employee_id IN ( 120 SELECT DISTINCT 121 manager_id 122 FROM 123 employees 124 ); 125 126 #7.各個部門中最高工資中最低的那個部門的最低工資是多少 127 SELECT 128 min(salary), 129 department_id 130 FROM 131 employees 132 WHERE 133 department_id = ( 134 SELECT 135 department_id 136 FROM 137 employees 138 GROUP BY 139 department_id 140 ORDER BY 141 max(salary) 142 LIMIT 1 143 ); 144 145 #8.查詢平均工資最高的部門的 manager的詳細資訊:last_name, department id, email 146 SELECT 147 last_name, 148 d.department_id, 149 email, 150 salary 151 FROM 152 employees e 153 JOIN departments d ON d.manager_id = e.manager_id 154 WHERE 155 d.department_id = ( 156 SELECT 157 department_id 158 FROM 159 employees 160 GROUP BY 161 department_id 162 ORDER BY 163 avg(salary) DESC 164 LIMIT 1 165 );