1. 題目

Given any string of N (≥5) characters, you are asked to form the characters into the shape of U. For example, helloworld can be printed as:

h  d
e  l
l  r
lowo

That is, the characters must be printed in the original order, starting top-down from the left vertical line with n1 characters, then left to right along the bottom line with n

Input Specification:

Each input file contains one test case. Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.

Output Specification:

For each test case, print the input string in the shape of U as specified in the description.

Sample Input:

helloworld!

Sample Output:

h   !
e   d
l   l
lowor

2. 題意

將一串字串以U型形式輸出出來。

3. 思路——字串

根據題意計算n1,n2,n3，這裡n1等於n3，只要定義n1和n2即可。

計算方法：

​ 已知：n1=n3=max {k | k≤n2 for all 3≤n2≤N }，且n1+n2+n3-2=N

​ 可得：\(n1=n3=(N+2)/2\)（結果向下取整）

​ \(n2=N+2-n1-n3\)

計算出n1和n2後，即可根據題目要求輸出U型圖形（見程式碼）。

4. 程式碼

#include <iostream>
#include <string>

using namespace std;

int main()
{
	string str;
	cin >> str;
	int n1, n2;
	int N = str.length();
	n1 = (N + 2) / 3;
	n2 = N + 2 - (2 * n1);
	for (int i = 0; i < n1 - 1; ++i)
	{
		// 輸出第i個字元 
		cout << str[i];	
		// 輸出中間的空格 
		for (int j = 0; j < n2 - 2; ++j) cout << " ";
		// 輸出倒數第i+1個字元 
		cout << str[N - 1 - i] << endl;	
	}
	// 最後一行輸出剩下的中間字串 
	cout << str.substr(n1 - 1, n2) << endl;
	return 0;
}