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WCF初探-22:WCF中使用Message類(上)

多校賽第二場B題

#include <bits/stdc++.h>
#define ll              long long
#define lll             unsigned long long
#define pii             pair<int, int>
#define rep(i,a,b)      for(ll  i=a;i<=b;i++)
#define dec(i,a,b)      for(ll  i=a;i>=b;i--)
#define forn(i, n)      for(ll i = 0; i < int(n); i++)
using
namespace std; int dir[4][2] = { { 1,0 },{ 0,1 } ,{ 0,-1 },{ -1,0 } }; const long long INF = 0x7f7f7f7f7f7f7f7f; const int inf = 0x3f3f3f3f; const double pi = 3.14159265358979323846; const double eps = 1e-6; const int mod = 998244353; const int N = 2e3 + 5; //if(x<0 || x>=r || y<0 || y>=c) inline ll read() { ll x
= 0; bool f = true; char c = getchar(); while (c < '0' || c > '9') { if (c == '-') f = false; c = getchar(); } while (c >= '0' && c <= '9') x = (x << 1) + (x << 3) + (c ^ 48), c = getchar(); return f ? x : -x; } ll gcd(ll m, ll n) { return n == 0 ? m : gcd(n, m % n); } ll lcm(ll m, ll n) {
return m * n / gcd(m, n); } bool prime(int x) { if (x < 2) return false; for (int i = 2; i * i <= x; ++i) { if (x % i == 0) return false; } return true; } inline int qpow(int x, ll n) { int r = 1; while (n > 0) { if (n & 1) r = 1ll * r * x % mod; n >>= 1; x = 1ll * x * x % mod; } return r; } inline int add(int x, int y) { return ((x % mod) + (y % mod)) % mod; } inline int sub(int x, int y) { x -= y; return x < 0 ? x += mod : x; } inline int mul(int x, int y) { return (1ll * (x % mod) * (y % mod)) % mod; } inline int inv(int x) { return qpow(x, mod - 2); } inline int divd(int x, int y) { return (1ll * (x % mod) * inv(y)) % mod; } int n, ans = 1, X[N], Y[N]; struct node { double x,y; node(): node(0,0){} node(double x,double y):x(x),y(y){} bool operator < (const node& r) { return (double)x*r.y<(double)y*r.x; } bool operator == (const node& r) { return (double)x*r.y==(double)y*r.x; } }; int Cross(int lhs, int rhs) { return X[lhs] * Y[rhs] - X[rhs] * Y[lhs]; } int Dot(int lhs, int rhs) { return X[lhs] * X[rhs] + Y[lhs] * Y[rhs]; } double Dis2(int lhs, int rhs) { double dx = X[lhs] - X[rhs], dy = Y[lhs] - Y[rhs]; return dx * dx + dy * dy; } int Sgn(int x) { if (x > 0) return 1; if (x < 0) return -1; return 0; } node ar[N]; node cos2(ll x, ll y) { ll a2=Dis2(0,x),b2=Dis2(x,y),c2=Dis2(0,y); int sgn=Sgn(b2+c2-a2); return node((double)1*sgn*(b2 + c2 - a2) * (b2 + c2 - a2), (double)4 * b2 * c2); } int main() { scanf("%d", &n); for (int i = 1; i <= n; i ++) scanf("%d%d", X + i, Y + i); for (int i = 1; i <= n; i ++) { int cnt = 0; for (int j = 1; j <= n; j ++) if (Cross(i, j) > 0) ar[++cnt]=cos2(i,j); sort(ar+1,ar+cnt+1); for(int l=1,r;l<=cnt;l=r) { for(r=l;ar[l]==ar[r] && r<=cnt;r++); ans=max(ans,r-l+1); } } printf("%d\n", ans); return 0; }