第五話-運算子
阿新 • • 發佈:2022-04-04
運算子總結
程式碼demo
package operator; public class Demo01 { public static void main(String[] args) { //二元運算子 //Ctrl + d : 複製當前行到下一行 int a = 10; int b = 20; int c = 25; int d = 25; System.out.println(a+b); System.out.println(a-b); System.out.println(a*b); System.out.println(a/(double)b); //運算子計算後型別轉換 long a1 = 123123123123L; int b1 = 123; short c1 = 10; byte d1 = 8; System.out.println(a1+b1+c1+d1); //Long System.out.println(b1+c1+d1); //Int System.out.println(c1+d1); //Int //關係運算符返回的結果: 正確,錯誤 布林值 int a2 = 10; int b2 = 20; int c2 = 21; System.out.println(c2%b2); System.out.println(a2>b2); System.out.println(a2<b2); System.out.println(a2==b2); System.out.println(a2!=b2); //++自增 --自減 一元運算子 int aa = 3; int bb = aa++; int cc = ++aa; System.out.println(aa); System.out.println(bb); System.out.println(cc); //Math工具類,冪運算,2^3=8,還支援很多數學函式 double pow = Math.pow(2, 3); System.out.println(pow); //邏輯運算子,與 或 非 boolean booa = true; boolean boob = false; System.out.println("booa&&boob:"+(booa&&boob)); //false,兩個都為真,則結果true System.out.println("booa||boob:"+(booa||boob)); //true,有一個為真,則結果true System.out.println("!(booa&&boob)"+!(booa&&boob));//true //短路運算:與運算,第一個為false,則無需繼續執行,第二個c++沒有執行。 int booc = 5; boolean bood = (c<5)&&(c++<5); System.out.println(bood + "," + booc); //位運算 /* A = 0011 1100 B = 0000 1101 ------ A&B = 0000 1100 //兩個都為1則結果是1 A|B = 0011 1101 //有一個為1則結果是1 A^B = 0011 0001 //相同為0,不同為1 ~B = 1111 0010 //取反 << *2 效率高 >> /2 0000 0010 2 0000 0100 4 0000 1000 8 0001 0000 16 */ System.out.println(2<<3); //2 (*2)三次 //擴充套件賦值運算子:+=,-=,*=,/= int aaa = 10; int bbb = 20; aaa+=bbb; //aaa = aaa + bbb System.out.println(aaa+","+bbb); //字串連線符 + System.out.println(aaa+bbb+""); System.out.println(""+aaa+bbb); //三元運算子: x ? y : z // 如果x==true,則結果為y,否則結果為z int score = 50; String type = score<60 ? "不及格" : "及格"; System.out.println(type); } }