原題傳送門

1. 問題描述

2. Solution

1、思路
注意重複字串的處理
2、實現
Java

package huawei.HJ020;

import java.io.IOException;
import java.nio.file.Paths;
import java.util.Scanner;

public class Main {
    static Scanner in;
    static String inputFileName = "/Users/jun/Documents/Learn/JavaLearning/NowCoder/src/huawei/HJ020/input.txt";

    static {
        if (!"Linux".equals(System.getProperty("os.name"))) {
            try {
                in = new Scanner(Paths.get(inputFileName));
            } catch (IOException e) {
                e.printStackTrace();
            }
        } else {
            in = new Scanner(System.in);
        }
    }

    public static void main(String[] args) {
        while (in.hasNext()) {
            String s = in.nextLine();
            System.out.println(solve(s));
        }
    }

    private static String solve(String s) {
        // 1.長度超過8位
        if (s.length() <= 8)
            return "NG";
        // 2.包括大小寫字母.數字.其它符號,以上四種至少三種
        boolean[] valid = new boolean[4];   // 大寫字母、小寫字母、數字、其他字元
        for (int i = 0; i < s.length(); i++) {
            char c = s.charAt(i);
            if (Character.isUpperCase(c))
                valid[0] = true;
            else if (Character.isLowerCase(c))
                valid[1] = true;
            else if (Character.isDigit(c))
                valid[2] = true;
            else if (!Character.isSpaceChar(c))
                valid[3] = true;
        }
        int cnt = 0;
        for (boolean elem : valid) {
            if (elem) cnt++;
        }
        if (cnt < 3)
            return "NG";
        // 3.不能有長度大於2的不含公共元素的子串重複 （注：其他符號不含空格或換行）
        for (int start = 3; start < s.length(); start++) {
            if (s.substring(start).contains(s.substring(start - 3, start)))
                return "NG";
        }
        return "OK";
    }
}

 

Python

import sys

if sys.platform != "linux":
    sys.stdin = open("input/HJ20.txt")


def solve(s):
    if len(s) <= 8:
        return "NG"
    valid = [0] * 4  # 大寫字母、小寫字母、數字、其他符號
    for c in s:
        if c.isupper():
            valid[0] = 1
        elif c.islower():
            valid[1] = 1
        elif c.isdigit():
            valid[2] = 1
        elif not c.isspace():
            valid[3] = 1
    if sum(valid) < 3:
        return "NG"
    for start in range(len(s) - 3):
        segment = s[start: start + 3]
        if len(s.split(segment)) >= 3:
            return "NG"
    return "OK"


for line in sys.stdin:
    print(solve(line.strip()))