C++ thread pass multiple functions and arguments via lambda expression
阿新 • • 發佈:2022-04-04
#include "Model/Util.h" char *Util::uuidValue = (char *)malloc(40); void Util::threadLambda6(int xx,int yy,string sstr) { thread t1([](int x,int y,string str) { cout<<endl; printNumUuid2(x); cout<<endl; printUuidNum3(y); cout<<endl; printStr(str); },xx,yy,sstr); t1.join(); }void Util::thread5(int xx,int yy,string sstr) { thread t1([](int x,int y,string str) { printNumUuid2(x); cout<<endl<<endl; printUuidNum3(y); cout<<endl<<endl; printStr(str); cout<<endl<<endl; },xx,yy,sstr); t1.join(); }void Util::printStr(string str) { cout<<str<<endl; cout<<"FILE:"<<__FILE__<<",FUNCTION:"<<__FUNCTION__<<",LINE:"<<__LINE__<<endl; } char *Util::getUuid1() { uuid_t newUUID; uuid_generate(newUUID); uuid_unparse(newUUID, uuidValue);return uuidValue; } void Util::printNumUuid2(int x) { Util ul; for(int i=0;i<x;i++) { cout<<"Num="<<i<<","<<ul.getUuid1()<<endl; } } void Util::printUuidNum3(int y) { Util ul; for(int i=0;i<y;i++) { cout<<ul.getUuid1()<<","<<i<<endl; } } int main(int args, char **argv) { try { threadLambda33(atoi(argv[1]),atoi(argv[2]),argv[3]); } catch (const std::exception &e) { cout << e.what() << endl; std::cerr << e.what() << '\n'; } return 0; } void threadLambda33(int x,int y,string str) { Util ul; ul.threadLambda6(x,y,str); }
g++ -g -std=c++2a -I. *.cpp ./Model/*.cpp -o h1 -luuid -lpthread