python os.isfile 判斷已有檔案不存在怎麼解決
阿新 • • 發佈:2022-04-19
實驗:工作路徑下有一個try.py
以及try.txt
import os print(os.getcwd()) # path\to\cwd print(os.path.isfile("./try.txt")) # True print(os.path.isfile(".\\try.txt")) # True print(os.path.isfile("try.txt")) path = os.path.join(os.path.dirname(__file__), ".\\try.txt") # path\to\cwd\.\try.txt True print(path, os.path.isfile(path)) path = os.path.join(os.path.dirname(__file__), "./try.txt") # path\to\cwd\./try.txt True print(path, os.path.isfile(path)) path = os.path.join(os.path.dirname(__file__), "try.txt") # path\to\cwd\try.txt True print(path, os.path.isfile(path)) path = f'"{path}"' # "path\to\cwd\try.txt" False print(path, os.path.isfile(path))
對於一個合法路徑path
,如果傳入的是"path"
這個帶有"
引號的字串,那麼系統將會認為檔案不存在
注意,如果路徑作為命令列引數傳入的話,會自動過濾掉引號python -u "path\to\cwd\try_path.py" -path "D:\try.txt"
print(sys.argv)
# ['path\\to\\cwd\\try_path.py', '-path', 'D:\\try.txt']