python本身也是通過向瀏覽器傳送請求獲取資料的，存在請求頭，如果不進行偽裝，會被對方伺服器識別從而爬取失敗

def askURL(url):
    data = bytes(urllib.parse.urlencode({
        "setAction": "classroomQuery",
        "PageAction": "Query",
        "day_time_text": "0011000000000",
        "school_area_code": "1",
        "building": "13",
        "week_no": "256"
 

        , "day_no": "2",
        "day_time1": "ON",
        "B1": "查詢"}), encoding="utf-8")
    headers = {  # 模擬瀏覽器頭部資訊，向瀏覽器傳送訊息
        "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:99.0) Gecko/20100101 Firefox/99.0"
    }
#使用者代理，表示告訴伺服器，我麼是什麼型別的機器，本質上是告訴瀏覽器，我們可以接受什麼型別的內容
    request=urllib.request.Request(url,headers=headers,data=data,method="
 
POST")
    html=""
    try:
        resonse = urllib.request.urlopen(request)
        html=resonse.read().decode("utf-8")
        #print(html)
    except urllib.error.URLError as e:
        if hasattr(e,"code"):
            print(e.code)
        if hasattr(e,"reason"):
            print(e.reason)
    
 
return html

偽裝請求頭headers

開啟任意網站開啟控制檯網路，複製請求頭即可