實驗四 函式與異常處理應用程式設計
阿新 • • 發佈:2022-05-10
task1
print(sum) sum = 42 print(sum) def inc(n): sum = n+1 print(sum) return sum sum = inc(7) + inc(7) print(sum)
1.內建函式名
2.賦值名
3.區域性變數
4.全域性變數
task2
def func1(a, b, c, d, e, f): '''返回引數a,b,c,d,e,f構成的列表 預設,引數按位置傳遞; 也支援關鍵字傳遞 ''' return [a,b,c,d,e,f] def func2(a, b, c,*, d, e, f):''' 返回引數a,b,c,d,e,f構成的列表 *後面的引數只能按關鍵字傳遞 ''' return [a,b,c,d,e,f] def func3(a, b, c, /, d, e, f): ''' 返回引數a,b,c,d,e,f構成的列表 /前面的引數只能按位置傳遞 ''' return [a,b,c,d,e,f] print( func1(1,9,2,0,5,3) ) print( func1(a=1, b=9, c=2, d=0, e=5, f=3) ) print( func1(1,9,2, f=3, d=0, e=5))print( func2(11, 99, 22, d=0, e=55, f=33) ) print( func2(a=11, b=99, c=22, d=0, e=55, f=33) ) print( func3(111, 999, 222, 0, 555, 333)) print( func3(111, 999, 222, d=0, e=555, f=333) )
def func(a, b, c, /, *, d, e, f): return( [a,b,c,d,e,f] ) print(func(1, 2, 3, d=4, e=5, f=6))
task3
def solve(a, b, c):''' 求解一元二次方程, 返回方程的兩個根 :para: a,b,c: int 方程係數 :return: tuple ''' delta = b*b - 4*a*c delta_sqrt = abs(delta)**0.5 p1 = -b/2/a; p2 = delta_sqrt/2/a if delta>=0: root1 = p1 + p2 root2 = p1 - p2 else: root1 = complex(p1, p2) root2 = complex(p1, -p2) return root1, root2 print(solve.__doc__) while True: try: a,b,c = eval(input('Enter eqution coefficient: ')) if a == 0: raise except: print('invalid input, or, a is zero') break else: root1, root2 = solve(a, b, c) print(f'root1 = {root1:.2f}, root2 = {root2:.2f}') print()
task4
def list_generator (begin,end,step=1): list=[] while begin<=end: list.append(begin) begin=begin+step return list list1=list_generator(-5, 5) print(list1) list2=list_generator(-5, 5, 2) print(list2) list3=list_generator(1, 5, 0.5) print(list3)
task5
def is_prime(n): if n < 2: return False for i in range(2,int(n**0.5)+1): if n % i == 0: return False return True h=[i for i in range(21)] for x in h[::2]: for a in range(0,21): if is_prime(a) is True: if is_prime(x-a) is True: print(f'{x}={a}+{x-a}') break else: a+=1 else: a+=1
task6
def encoder(strs): a=list(strs) i=0 while i <len(strs): b = ord(a[i]) if 65<=b<=85 or 97<=b<=117: c=chr(b+5) elif 85<=b<=90 or 117<=b<=122: c=chr(b-21) else: c=chr(b) a[i]=c i+=1 return ''.join(a) def decoder(strs): a = list(strs) i=0 while i < len(strs): b = ord(a[i]) if 70<=b<=90 or 102<=b<=122: c=chr(b-5) elif 65<=b<=70 or 97<=b<=102: c=chr(b+21) else: c=chr(b) a[i] = c i+=1 return ''.join(a) a=input('輸入英文文字: ') print(f'編碼後的文字:{encoder(a)}') print(f'對編碼後的文字解碼:{decoder(encoder(a))}')
task7
def collatz(n): x=[n] while n!=1: if n%2==0: n=n/2 else: n=3*n+1 x.append(int(n)) return x try: n=int(input('Enter a positive integer:')) if n<=0: raise except: print('Error: must be a positive integer') else: print(collatz(n))