SQL Server檢視login所授予的具體許可權問題
阿新 • • 發佈:2020-01-09
在SQL Server資料庫中如何檢視一個登入名(login)的具體許可權呢,如果使用SSMS的UI介面檢視登入名的具體許可權的話,使用者資料庫非常多的話,要梳理完它所有的許可權,操作又耗時又麻煩,個人十分崇尚簡潔、高效的方法,反感那些需要大量手工操作的UI介面操作方式,哪怕就是指令碼,如果不能一次搞定,手工多操作幾次(例如,切換資料庫),都是不可接受的。最近遇到這個需求,就完善了一下之前的指令碼get_login_rights_script.sql,輸入登入名引數,將這個登入名所擁有的伺服器角色、資料庫角色、以及所授予具體物件的相關許可權使用指令碼查詢出來,指令碼分享如下:
--================================================================================================================== -- ScriptName : get_login_rights_script.sql -- Author : 瀟湘隱者 -- CreateDate : 2015-12-18 -- Description : 檢視某個登入名被授予的資料庫物件的許可權的指令碼(授權指令碼和回收許可權指令碼) -- Note : /****************************************************************************************************************** Parameters : 引數說明 ******************************************************************************************************************** @login_name : 你要檢視許可權的登入名(需要輸入替換的引數) ******************************************************************************************************************** Modified Date Modified User Version Modified Reason ******************************************************************************************************************** 2018-08-03 瀟湘隱者 V01.00.00 新建該指令碼。 2019-04-04 瀟湘隱者 V01.01.00 Fix掉一個bug,某個表只允許更新某個欄位,但是這裡顯示更新整個表。 2019-09-25 瀟湘隱者 V01.02.00 解決只能檢視某個使用者資料庫,不能檢視所有資料庫的許可權問題。 2019-09-25 瀟湘隱者 V01.03.00 解決資料庫名包含中劃線[-],出現下面錯誤問題 ------------------------------------------------------------------------------------------------------------------- Msg 911,Level 16,State 1,Line 1 Database 'xxxx' does not exist. Make sure that the name is entered correctly. ------------------------------------------------------------------------------------------------------------------- *******************************************************************************************************************/ DECLARE @login_name NVARCHAR(32)= 'test1'; DECLARE @database_name NVARCHAR(64); DECLARE @cmdText NVARCHAR(MAX); IF OBJECT_ID('TempDB.dbo.#databases') IS NOT NULL DROP TABLE dbo.#databases; CREATE TABLE #databases ( database_id INT,database_name sysname ); IF OBJECT_ID('tempdb.dbo.#user_db_roles') IS NOT NULL DROP TABLE dbo.#user_db_roles; CREATE TABLE dbo.#user_db_roles ( [DB_NAME] NVARCHAR(64),[USER_NAME] NVARCHAR(64),[ROLE_NAME] NVARCHAR(64) ); IF OBJECT_ID('tempdb.dbo.#user_object_rights') IS NOT NULL DROP TABLE dbo.#user_object_rights; CREATE TABLE dbo.#user_object_rights ( [DATABASE_NAME] NVARCHAR(128),[SCHEMA_NAME] NVARCHAR(64),[OBJECT_NAME] NVARCHAR(128),[USER_NAME] NVARCHAR(32),[PERMISSIONS_TYPE] CHAR(12),[PERMISSION_NAME] NVARCHAR(128),[PERMISSION_STATE] NVARCHAR(64),[CLASS_DESC] NVARCHAR(64),[COLUMN_NAME] NVARCHAR(32),[STATE_DESC] NVARCHAR(64),[GRANT_STMT] NVARCHAR(MAX),[REVOKE_STMT] NVARCHAR(MAX) ) INSERT INTO #databases SELECT database_id,name FROM sys.databases WHERE name NOT IN ('model') AND state = 0; --state_desc=ONLINE --登入名授予的伺服器角色 SELECT UserName = u.name,ServerRole = g.name,Type = u.type,Type_Desc = u.Type_Desc,Create_Date = u.create_date,Modify_Date = u.modify_date,DenyLogin = l.denylogin FROM sys.server_role_members m INNER JOIN sys.server_principals g ON g.principal_id = m.role_principal_id INNER JOIN sys.server_principals u ON u.principal_id = m.member_principal_id INNER JOIN sys.syslogins l ON u.name = l.name WHERE l.name=@login_name ORDER BY u.name,g.name; WHILE 1= 1 BEGIN SELECT TOP 1 @database_name= database_name FROM #databases ORDER BY database_id; IF @@ROWCOUNT =0 BREAK; SET @cmdText = N'USE ' + QUOTENAME(@database_name) + N';' +CHAR(10) --登入名授予的資料庫角色 SELECT @cmdText += N'INSERT INTO #user_db_roles SELECT DB_NAME() AS [DB_NAME],M.NAME AS [USER_NAME],R.NAME AS [ROLE_NAME] FROM sys.DATABASE_ROLE_MEMBERS RM INNER JOIN sys.DATABASE_PRINCIPALS R ON RM.ROLE_PRINCIPAL_ID = R.PRINCIPAL_ID INNER JOIN sys.DATABASE_PRINCIPALS M ON RM.MEMBER_PRINCIPAL_ID = M.PRINCIPAL_ID WHERE M.NAME=@p_login_name' + CHAR(10); EXEC SP_EXECUTESQL @cmdText,N'@p_login_name NVARCHAR(32)',@p_login_name=@login_name; SET @cmdText = N'USE ' +QUOTENAME(@database_name) + N';' +CHAR(10); --檢視具體物件的授權問題 SELECT @cmdText +=N'INSERT INTO dbo.#user_object_rights ( [DATABASE_NAME],[SCHEMA_NAME],[OBJECT_NAME],[USER_NAME],[PERMISSIONS_TYPE],[PERMISSION_NAME],[PERMISSION_STATE],[CLASS_DESC],[COLUMN_NAME],[STATE_DESC],[GRANT_STMT],[REVOKE_STMT] ) SELECT DB_NAME() AS [DATABASE_NAME],SYS.SCHEMAS.NAME AS [SCHEMA_NAME],ob.NAME AS [OBJECT_NAME],SYS.DATABASE_PRINCIPALS.NAME AS [USER_NAME],dp.TYPE AS [PERMISSIONS_TYPE],dp.PERMISSION_NAME AS [PERMISSION_NAME],dp.STATE AS [PERMISSION_STATE],dp.CLASS_DESC AS [CLASS_DESC],sc.name AS [COLUMN_NAME],dp.STATE_DESC AS [STATE_DESC],dp.STATE_DESC + '' '' + dp.PERMISSION_NAME + '' ON [''+ SYS.SCHEMAS.NAME + ''].['' + ob.NAME + ''] TO ['' + SYS.DATABASE_PRINCIPALS.NAME + ''];'' COLLATE LATIN1_GENERAL_CI_AS AS [GRANT_STMT],''REVOKE '' + dp.PERMISSION_NAME + '' ON [''+ SYS.SCHEMAS.NAME + ''].['' + ob.NAME + ''] FROM ['' + SYS.DATABASE_PRINCIPALS.NAME + ''];'' COLLATE LATIN1_GENERAL_CI_AS AS [REVOKE_STMT] FROM SYS.DATABASE_PERMISSIONS dp LEFT OUTER JOIN SYS.OBJECTS ob ON dp.MAJOR_ID = ob.OBJECT_ID LEFT OUTER JOIN SYS.SCHEMAS ON ob.SCHEMA_ID = SYS.SCHEMAS.SCHEMA_ID LEFT OUTER JOIN SYS.DATABASE_PRINCIPALS ON dp.GRANTEE_PRINCIPAL_ID = SYS.DATABASE_PRINCIPALS.PRINCIPAL_ID LEFT OUTER JOIN SYS.columns sc ON ob.object_id = sc.object_id AND sc.column_id = dp.minor_id WHERE SYS.DATABASE_PRINCIPALS.NAME =@p_login_name ORDER BY PERMISSIONS_TYPE;' PRINT(@cmdText); EXEC SP_EXECUTESQL @cmdText,@p_login_name=@login_name; DELETE FROM #databases WHERE database_name=@database_name; END SELECT * FROM tempdb.dbo.#user_db_roles; SELECT * FROM dbo.#user_object_rights; IF OBJECT_ID('TempDB.dbo.#databases') IS NOT NULL DROP TABLE dbo.#databases; IF OBJECT_ID('tempdb.dbo.#user_db_roles') IS NOT NULL DROP TABLE dbo.#user_db_roles; IF OBJECT_ID('tempdb.dbo.#user_object_rights') IS NOT NULL DROP TABLE dbo.#user_object_rights;
總結
以上所述是小編給大家介紹的SQL Server檢視login所授予的具體許可權問題,希望對大家有所幫助,如果大家有任何疑問請給我留言,小編會及時回覆大家的。在此也非常感謝大家對我們網站的支援!
如果你覺得本文對你有幫助,歡迎轉載,煩請註明出處,謝謝!