第一題：將 a = [1,1,1,2,2,3,3,3,4,5,6,6,6,7,8,8]轉化為c = [1,1,2,2,3,3,4,5,6,6,7,8]

分析：對出現相同元素次數大於2的進行處理

a = [1,1,1,2,2,3,3,3,4,5,6,6,6,7,8,8]
# c = [1,1,2,2,3,3,4,5,6,6,7,8]
b = []
for i in a:

    if b.count(i) < 2:

        b.append(i)

print(b)

第二題：找出字串中重複的內容

f = "asklabassk"

def find_distinct(string):

    l1 
 
=[] # 去重的
    l2 =[] # 重複的
    for i in range(0, len(string)):

        if string[i] in l1:

            l2.append(string[i])
        else:
            l1.append(string[i])
    return  set(l2)


f = "asklabassk"

res = find_distinct(f)
print(res)
--------------------------
{'s', 'a', 'k'}

第三題：統計字串中元素出現的次數

def count_each_char_1(string):
    res = {}
    for i in string:
        if i not in res:
            res[i] = 1
        else:
            res[i] += 1
    return res


print(count_each_char_1('aenabsascd'))

------------------------------
{'a': 3, 'e': 1, 'n': 1, 'b': 1, 's': 2, 'c': 1, 'd': 1}