字串排序(HJ26)
阿新 • • 發佈:2020-08-06
一:解題思路
二:完整程式碼示例 (C++版和Java版)
C++程式碼:
#include <iostream> #include <vector> #include <string> using namespace std; int main() { string str = ""; while (cin >> str) { vector<char> result; for (int j = 0; j < 26; j++) {for (int i = 0; i < str.size(); i++) { if (str[i] - 'a' == j || str[i] - 'A' == j) { result.push_back(str[i]); } } } int index = 0; for (int i = 0; i < str.size(); i++) {if ((str[i] >= 'A' && str[i] <= 'Z') || (str[i] >= 'a' && str[i] <= 'z')) { if (index < result.size()) { cout << result[index]; index++; } }else { cout << str[i]; } } cout << endl; } return 0; }