Python判斷字串是否為合法標示符操作
阿新 • • 發佈:2020-09-03
這學期在學習編譯原理,最近的上機作業就是做一個簡單的詞法分析器,在做的過程中,突然有個需求就是判斷一個字串是否為合法的標示符,因為我是用python語言做的,做的是Python的詞法分析器,於是下面分享以下怎樣判斷一個字串是合法的標示符。
首先,我們來熟悉以下python標示符的定義是什麼?
定義:以字母或下劃線開始的,由字母,數字或下劃線組成,但是不能是python的保留字。
又有疑問了,python有哪些保留字,分別是什麼?
# python2.x import keyword print keyword.kwlis # python3.x import keyword print(keyword.kwlist) # python2.x輸出: ['and','as','assert','break','class','continue','def','del','elif','else','except','exec','finally','for','from','global','if','import','in','is','lambda','not','or','pass','print','raise','return','try','while','with','yield'] # 共31個 # python3.x輸出: ['False','None','True','and','nonlocal','yield'] # 共33個
好了,下面開始判斷
# python2.7 #!/usr/bin/env python # -*- coding: UTF-8 -*- import keyword import string def is_signal(s): kw = keyword.kwlist if s in kw: return 0 elif s[0] == '_' or s[0] in string.letters: # 判斷是否為字母或下劃線開頭 for i in s: if i == '_' or i in string.letters or i in string.digits: # 判斷是否由字母數字或下劃線組成 pass else: return 0 return 1 else: return 0 def main(): s = raw_input() if is_signal(s) == 1: print "True" else: print "False" if __name__ == '__main__': main() # python3.4 #!/usr/bin/env python # -*- coding: UTF-8 -*- import keyword import string def is_signal(s): kw = keyword.kwlist if s in kw: return 0 elif s[0] == '_' or s[0] in string.ascii_letters: # 判斷是否為字母或下劃線開頭 for i in s: if i == '_' or i in string.ascii_letters or i in string.digits: # 判斷是否由字母數字或下劃線組成 pass else: return 0 return 1 else: return 0 def main(): s = input() if is_signal(s) == 1: print("True") else: print("False") if __name__ == '__main__': main()
通過鍵盤輸入判斷,是標示符,則返回True,否則返回False
補充知識:python:識別符號必須以字母或下劃線開頭,後面跟字母,下劃線或者數字
標識符合法性檢查,首先要以字母或者下劃線開始,後面要跟字母,下劃線或者或數字.這個小例子只檢查長度大於等於 2 的識別符號
idcheck.py
#!/usr/bin/env python ''' idcheck.py -- checks identifiers for validity ''' import string # string utility module # create alphabet and number sets alphas = string.ascii_letters + '_' nums = string.digits # salutation message and input prompt print ('Welcome to the Identifier Checker v1.0') print ('Testees must be at least 2 chars long.') inp = input('Identifier to test ?') if len(inp) >= 1: if inp[0] not in alphas: print ('invalid: first symbol must be alphabetic') else: for otherChar in inp[1:]: if otherChar not in alphas + nums: print ('invalid: remaining symbols must be alphanumeric') break else: print ("okay as an identifier") else: print ('invalid: length must be >= 1')
執行結果 1:
Welcome to the Identifier Checker v1.0 Testees must be at least 2 chars long. Identifier to test -> 123_das invalid: first symbol must be alphabetic
執行結果 2:
Welcome to the Identifier Checker v1.0 Testees must be at least 2 chars long. Identifier to test -> _123sdad okay as an identifier
以上這篇Python判斷字串是否為合法標示符操作就是小編分享給大家的全部內容了,希望能給大家一個參考,也希望大家多多支援我們。