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阿新 • • 發佈:2017-05-08
div efi cnblogs 表示 進制 memset bound col scan
1 #include<bits/stdc++.h> 2 3 const int Maxn = 1000005; 4 5 #define ll long long 6 using namespace std; 7 int x[Maxn], pos[33]; 8 int main() { 9 int T, N; 10 cin >> T; 11 while (T--) { 12 scanf("%d", &N); 13 for (int i = 0; i < N; i++) scanf("%d", &x[i]);View Code14 sort(x, x + N); 15 16 long long ans = 0; 17 for (int i = 1; i < N; i++) { 18 memset(pos, 0, sizeof(pos)); 19 20 int k = x[i], cnt = 0, p = 0; // cnt -> x[i]二進制中0的個數,p表示0的位置 21 while (k) { 22 if ((k & 1) == 0) pos[cnt++] = p;23 k >>= 1; 24 p++; 25 } 26 27 for (int j = 0; j < cnt; j++) { 28 int a = 1 << pos[j], b = (1 << (pos[j] + 1)) - 1; 29 ans += upper_bound(x, x + i, b) - lower_bound(x, x + i, a); 30 }31 } 32 printf("%lld\n", ans); 33 } 34 }
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