Given a word, you need to judge whether the usage of capitals in it is right or not.

We define the usage of capitals in a word to be right when one of the following cases holds:

1. All letters in this word are capitals, like "USA".
2. All letters in this word are not capitals, like "leetcode".
3. Only the first letter in this word is capital if it has more than one letter, like "Google".

Otherwise, we define that this word doesn‘t use capitals in a right way.

Example 1:

Input: "USA"
Output: True

Example 2:

Input: "FlaG"
Output: False

Note: The input will be a non-empty word consisting of uppercase and lowercase latin letters.

很簡單的一道題，渣渣如我只能暴力求解：

1.brutal force/命令式編程

 1 public
 
 class Solution {
 2     public boolean detectCapitalUse(String word) {
 3         char[] value = word.toCharArray();
 4         if(value.length == 1 || word == null) {
 5             return true;
 6         }
 7         boolean secIsUC = false;
 8         if(Character.isLowerCase(value[0])) {
 9             for
 
(int i=1; i<value.length; i++) {
10                 if(Character.isUpperCase(value[i])) {
11                     return false;
12                 }
13             }
14         } else {
15             secIsUC = Character.isUpperCase(value[1]) ? true : false;
16             if(secIsUC) {
17                 for(int i=2; i<value.length; i++) {
18                     if(Character.isLowerCase(value[i])) {
19                         return false;
20                     }
21                 }
22             } else {
23                 for(int i=2; i<value.length; i++) {
24                     if(Character.isUpperCase(value[i])) {
25                         return false;
26                     }
27                 }
28             }
29         }
30         return true;
31     }
32 }

2.暴力求解升級版

1 public class Solution {
2     public boolean detectCapitalUse(String word) {
3         int cnt = 0;
4         for(char c: word.toCharArray()) if(‘Z‘ - c >= 0) cnt++;
5         return ((cnt==0 || cnt==word.length()) || (cnt==1 && ‘Z‘ - word.charAt(0)>=0));
6     }
7 }

3.聲明式編程

1 public boolean detectCapitalUse(String word) {
2         if (word.length() < 2) return true;
3         if (word.toUpperCase().equals(word)) return true;
4         if (word.substring(1).toLowerCase().equals(word.substring(1))) return true;
5         return false;
6 }

4.RegEx

1 public boolean detectCapitalUse(String word) {
2     return word.matches("[A-Z]+|[a-z]+|[A-Z][a-z]+");
3 }

字符串（1）——Detect Capital