get top level domain name
url = window.location.hostname; // get host name like http://www.baidu.com
var res = url.split(‘.‘); // split by dot
var top_level_domain = res[res.length - 1]; // get last element in array
console.log(top_level_domain); // com
get top level domain name
相關推薦
get top level domain name
location oca length com dom ati log dot console url = window.location.hostname; // get host name like http://www.baidu.com var res =
get top level domain by php
else pos -- php top emp empty pty complete function rLastParse($str, $sep, $cnt = 1, $complete_if_not = false){ $i = strrpos($str, $sep);
Ask HN: Can weird and wonderful alternate top level domain names be trusted?
What if the owning company of the TLD goes out of business?Is it risky to build your business on an alternate TLD?
DDNS-dynamic domain name servers
sting normal stat lower network use aso script comm If you want to set up a server in your home work to provide some services to external
解決Cannot find config.m4 Make sure that you run '/home/php/bin/phpize' in the top level source directory of the module
編譯安裝 -o rec 找不到 extension home ring ins 擴展 oot@DK:/home/daokr/downfile/php-7.0.0/ext/mysqlnd# /home/php/bin/phpizeCannot find config.m4.
Node.js中module文件定義的top-level變量為何是私有的
size file 模塊 node api export 參考 mil -s 在Node.js中,module文件裏面使用var,const或者let定義的top-level變量為何是私有的,只能在這個模塊文件中使用呢? 原因就是,在模塊文件中的內容執行之前,node.js
【ADNI】資料預處理(5)Get top k slices (pMCI_sMCI) according to CNNs
ADNI Series 1、【ADNI】資料預處理(1)SPM,CAT12 2、【ADNI】資料預處理(2)獲取 subject slices 3、【ADNI】資料預處理(3)CNNs 4、【ADNI】資料預處理(4)Get top k slices according to CNN
【ADNI】資料預處理(4)Get top k slices according to CNNs
ADNI Series 1、【ADNI】資料預處理(1)SPM,CAT12 2、【ADNI】資料預處理(2)獲取 subject slices 3、【ADNI】資料預處理(3)CNNs 4、【ADNI】資料預處理(4)Get top k slices according to CNN
ValueError: attempted relative import beyond top-level package
python 專案 在pycharm中, 在某個資料夾下: 右鍵--> mark directory as --> source root 如何在python指令碼或者shell中 用程式碼實現 pycharm的資料夾 mark directory as so
頂級(top-level)元素,塊級(block-level)元素和內聯(inline)元素.
學習html後, 你會了解一些基本的html元素(Element), 如p, h1~h6, br, div, li, ul, img等.如果將這些元素細分, 又可以分別歸為頂級(top-level)元素,塊級(block-level)元素和內聯(inline)元素. 1.&n
初識域名系統DNS(Domain Name Server)
1.由來:IP地址不易記憶,用便於記憶的主機名替代IP地址作為輸入,訪問因特網。 2.作用:將主機名解析成IP地址,實現應用程序間通訊。 3.歷史:1)ARPANET時代,網路中計算機數量少,所有主機名字和相應的IP地址記錄於Hosts檔案中,只要使用者輸入主機名,計算機
httpd: Could not reliably determine the server's fully qualified domain name
httpd: Could not reliably determine the server’s fully qualified domain name, using 127.0.0.1 for ServerName 解決辦法非常簡單: #vim /web/apache/conf/h
PAT (Top Level) Practice1004 To Buy or Not to Buy - Hard Version (35 分)
題目連結:https://pintia.cn/problem-sets/994805148990160896/problems/994805155206119424 暴力,基本上不會超時,dfs加上一些剪枝 演算法:dfs #include<iostream> #includ
PAT (Top Level) Practice 1003 Universal Travel Sites (35 分)
題目連結:https://pintia.cn/problem-sets/994805148990160896/problems/994805155688464384 題很難理解,但其實就是普通的 網路流最大流(從源點到匯點可以運送的最大乘客)。建圖用stl。 演算法:網路流最大流(Dinic
PAT (Top Level) Practice1002 Business
題目連結:https://pintia.cn/problem-sets/994805148990160896/problems/994805156145643520 很入門的動態規劃題,一開始需要先排序。 演算法:dp/揹包 #include<iostream> #inclu
PAT (Top Level)Practice 1001 Battle Over Cities - Hard Version (35 分)
題目連結:https://pintia.cn/problem-sets/994805148990160896/problems/994805156657348608 主要考連通性 ,簡單來說就是列舉刪除每個點的最小生成樹的最大的花費是多少,注意如果不能聯通那麼一定是最大的,最後在遍歷
PAT (Top Level) Practice 1017 The Best Peak Shape (35 分)
這道題的連結:https://pintia.cn/problem-sets/994805148990160896/problems/994805150479138816 這道題很明顯是考最長遞增序列,用LIS O(NlgN)演算法,從網上看了別人寫的大多用dp但耗時太長,
PAT (Top Level) Practice1007 Red-black Tree (35 分)
題目連結:https://pintia.cn/problem-sets/994805148990160896/problems/994805153880719360 參考部落格:https://blog.csdn.net/u014646950/article/details/48683081
PAT (Top Level) Practice1006 Tree Traversals - Hard Version (35 分)
題目連結:https://pintia.cn/problem-sets/994805148990160896/problems/994805154321121280 dfs加剪枝,很麻煩,具體看程式碼。 演算法:dfs #include <cstdio> #include &
PAT (Top Level) Practice1005 Programming Pattern (35 分)
題目連結:https://pintia.cn/problem-sets/994805148990160896/problems/994805154748940288 用字尾陣列求出長度為n所有子字串的大小關係,然後得出重複最多的。 演算法:字尾陣列 #include<iostrea