Reverse digits of an integer.

Example1: x = 123, return 321
Example2: x = -123, return -321

Note:
The input is assumed to be a 32-bit signed integer. Your function should return 0 when the reversed integer overflows.

定位：簡單題

將輸入的數反轉輸出，註意的是負數符號保持在最前，反轉後的值超出int_32bit範圍輸出0。

簡單的將傳如的數分離符號後用StringBuffer進行反轉，然後轉化為int，此時嘗試抓取NumberFormatException的錯誤，如有直接為0。

Java實現：

 1 public class Solution {
 2     public int reverse(int x) {
 3         boolean isNev=false;
 4         if(x<0){
 5             x=-x;
 6             isNev=true;
 7         }
 8         StringBuffer stringBuffer=new StringBuffer(String.valueOf(x));
 9         stringBuffer=stringBuffer.reverse();
 
10         int y;
11         try{
12             y=Integer.parseInt(stringBuffer.toString());
13         }catch (NumberFormatException e){
14             y=0;
15         }
16         if(isNev){
17             y=-y;
18         }
19         return y;
20     }
21 }

LeetCode 007 Reverse Integer - Java